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2 years ago

15

Brandon mows his lawn once every 4 days. Thomas mows his lawn once every 3 days. Celena mows her lawn once every 6 days. If they

are all mowing the lawn today, in how many days will they be mowing their lawns together again?

2 answers:

lakkis [162]2 years ago

7 0

Answer: The Answer is 12

Step-by-step explanation: This is because each number's LCM (Least Common Multiple) is 12. Ex. 4,8,12 3,6,9,12 6,12

Murljashka [212]2 years ago

3 0

Answer:

24 days

Step-by-step explanation:

Given that;

Brandon mows his lawn once every 4 days, Thomas mows his lawn once every 3 days. Celena mows her lawn once every 6 days. Then assuming today is day 1,

Brandon will mows his lawn on the following dates

1,5,9,13,17,21,25,29 (adding 4 days)

Thomas will mows his lawn on the following dates

1,4,7,10,13,16,19,22,25,28 (adding 3 days)

Celena will mows her lawn on the following dates

1,7,13,19,25,31 (adding 6 days)

Comparing all the days, all 3 will mow their lawns on the 25th which is 24 days after the first day.

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In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t

victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is $p =\frac{1}{5}$

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5

b

The mean is $\mu = 20$

The standard deviation is $\sigma=4$

c

The probability, $P =0.0002$

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability $Pe = 0.0003$

The probabilities $P \approx Pe$

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

$p =\frac{1}{5}$

$=0.2$

The mean of this distribution is mathematical represented as

$\mu = np$

substituting the value

$\mu = 100 * 0.2$

$\mu = 20$

The standard deviation is mathematically represented as

$\sigma = \sqrt{np (1-p)}$

substituting the value

$= \sqrt{100 * 0,2 (1-0.2)}$

$\sigma=4$

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

$P=P(X \ge 34 )$

By standardizing the normal approximation we have that

$P(X \ge 34) \approx P(Z \ge z)$

Now z is mathematically evaluated as

$z = \frac{x-\mu}{\sigma }$

Substituting values

$z = \frac{34-20}{4}$

$=3.5$

So using the z table the $P(Z \ge 3.5)$ is 0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

6 0

2 years ago

What is the solution of (4x-16)1/2=36^

MArishka [77]

Answer:

Answer is x=328 .

Step-by-step explanation:

solution= (4x-16)^1/2=36

squaring both sides we get

4x-16=129

4x=1296+16

x=(1296+16)/4

x=328 .

8 0

2 years ago

Read 2 more answers

A ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s. The radius of the ride is 9.0 meters. Which of th

lana [24]

Answer with explanation:

It is given that , ride at an amusement park moves the riders in a circle at a rate of 6.0 m/s.

$a=\frac{dv}{dt}=6 m/s$

Radius of Circle = 9.0 meters

Acceleration is rate of change of velocity,which will be perpendicular to radius vector.

Also, in terms of mathematics, line from center that is radius , to point of contact that is tangent line ,which is on the circle are perpendicular to each another.

→r(radius vector) ⊥ a(Acceleration vector).

So, In option A, Radius vector is Perpendicular to acceleration of riders.

4 0

2 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

so

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

so

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

so

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

2 years ago

At a bus station, buses begin their routes at 6 a.M. The schedule for two of the buses is based on the time intervals listed bel

Marianna [84]

Answer:

The next time both will leave the bus station at the same time is 7:15 a.m.

Step-by-step explanation:

Since 15 and 75 are multiples to each other.

So, L.C.M. of 15 and 75 is 75.

So, after 75 minutes both buses will leave the station at the same time.

Also since buses begin their routes at 6 a.m.

So, next time they will meet at

6 hours 0 minutes + 75 minutes = 7 hours 15 minutes = 7:15 a.m.

7 0

2 years ago