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aniked [119]
2 years ago
8

Which of the following lies between the cerebrum and the brain stem?A) medulla oblongataB) ponsC) mesencephalonD) diencephalonE)

cerebellum
Biology
1 answer:
In-s [12.5K]2 years ago
7 0

Answer:

Diencephalon

Explanation:

Brain stem and cerebrum are connected through diencephalon. It is a part of forebrain and carries sensory information and autonomic functions of the peripheral nervous system are also controlled by it. The brain stem is present beneath the cerebrum and cerebellum lies in front of it. It progresses from above the cerebrum and is connected to the spinal cord below. Medulla oblongata, one and midbrain are part of the brain stem

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In chloroplasts, ATP is synthesized from ADP plus inorganic phosphate (Pi) in a reaction catalyzed by ATP synthase molecules tha
garik1379 [7]

Explanation:

<em>Complete Question:</em>

<em>A. Blocking electron flow from one carrier to the next in the electron transport chains blocks formation of a proton gradient in the thylakoid. </em>

<em>B. Increasing the proton concentration difference across the thylakoid membrane is not associated with a parallel increase in the rate of ATP synthesis. </em>

<em>C. No ATP is synthesized when channel proteins that allow the free passage of protons are inserted into the thylakoid membrane. </em>

<em>D. No ATP is synthesized while the Calvin cycle is synthesizing carbohydrates and using ATP and NADPH at a high rate. </em>

Correct: C. No ATP is synthesized when channel proteins that allow the free passage of protons are inserted into the thylakoid membrane.

Photophosphorylation describes a process in which the H+ made in previous steps of photosynthesis, and free electrons are used to obtain energy stored as ATP; in the electron transport chain move down the chain the energy they release is used in pumping protons out of the thykaloid space.

The high concentration of  H+ from photolysis, outside the leads to increased H+ concentration within the thykaloid space, due to its high permeability.  This forms a gradient where there is a differential in the number of protons on either side of the membrane the protons flow into the stroma through the enzyme ATP synthase, which makes the energy storage molecules of ATP from the reduction of ADP and inorganic phosphate, Pi. NAD+ functions as the terminal electron acceptor and is reduced to NADPH.

Thus:

  • a H+ concentration gradient is required for oxidative phosphorylation in the electron transport chain of the chloroplast, and thus the production of ATP
  • the H+ ion gradient must favor the flow of electrons into the stroma

The free flow of H+ disrupts the gradient, and H+ cannot flow into ATP synthase to produce ATP.

Further Explanation:

Photosynthesis is a chemical pathway that’s integral to producing energy in plants and other primary producers. Energy in the form of molecules of glucose is produced from light, water and carbon dioxide while oxygen is released. This occurs in several complex steps, photosynthesis is a rate limited reaction, depends on several factors including carbon dioxide concentration, ambient temperature and light intensity; the energy is retrieved from photons, I.e. particles of light, and water is used as a reducing agent. This occurs in the thykaloids, where pigment molecules like chlorophyll reside.

The chloroplast is a membrane bound organelle found in plants. It contains several invaginations of a plasma membrane called the thylakoid membrane. This contains chlorophyll pigments, in stacks called granum, while the internal spaces of the organelle are called the lumen. Liquid surrounds the granum, forming the stroma.

During the light reaction:

  • Light is absorbed by pigments in phosystem II (PSII). This energy is transferred among pigments til it gets to the reaction center, and is transferred to P680; this promotes an electron to a higher energy level where it then goes to an acceptor molecule.
  • Water supplies the chlorophyll in plant cell with replacement electrons for the ones removed from photosystem II. Additionally, water (H2O) split by light during photolysis into H+ and OH- acts as a source of oxygen along with functioning as a reducing agent.
  • the electron moves down an electron transport chain (to PS I)where it experiences continuous energy loss. This energy fuels the pumping of H+ from the stroma to thykaloid, leading to the formation of a gradient. The H+ move along their gradient and cross through ATP synthase, into the the stroma.
  • ATP synthase converts ADP and Pi to the energy storage molecule ATP.
  • The electron gets to photosystem I where it goes to pigments at P700. It absorbs light energy, the electron is promoted to a higher energy level, and passed to an electron acceptor. This leaves a space for another electron which is then replaced by one from photosystem II.
  • in the ETC, the molecule NADP is reduced to NADPH by providing H+ ions. NADP and NADPH are integral to the Calvin cycle where monosaccharides or sugars like glucose are produced after the modification of several molecules.

Learn more about photosynthesis at brainly.com/question/4216541

Learn more about cellular life at brainly.com/question/11259903

#LearnWithBrainly

6 0
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Many scientists believe that the formation process of other terrestrial planets in our solar system was similar to the formation
Romashka [77]

For any terrestrial planet in the solar system, the core would be the densest layer, and the crust would be the least dense layer.

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A student models moon phases. She holds a foam ball on a stick in front of her body and then stands in front of a light as shown
mr Goodwill [35]

Answer:

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A fish has a head 9 inches long. the tail is equal to the size of the head plus one half the size of the body. the body is the s
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So let’s substitute that into the third equation and solve for B. B = H + T B = 9 + (9 + 1/2B) B = 18 + 1/2B Then subtract 1/2B from both sides: 1/2B = 18 Multiply both sides by two: B = 36 Now we know the value of B and the value of H. Substitute this back into the second equation and solve for T. T = H + 1/2B T = 9 + (1/2)36 T = 9 + 18 = 27 Step 4: Plug all values of H, T, and B into the final equation. Total length of fish = H + T + B Total length of fish = 9 +27 + 36 = 72.

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A conservation plan could proceed with a single 20-square kilometer habitat preserve or with two habitat preserves, measuring a
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A conversational plan with two habitat preserves, measuring a total of 20 square kilometers combined will preserve more species because this cause segregation of species based on their adaptability towards a safer and secure environment. For example if a lion and deer try to live in the same conservation area, then it’s obvious that the life of deer is always at risk. But in cases of segregated preserved areas both herbivorous and carnivorous animals can live separately. Also if there is special inclination of one species towards other then also these two species can live separately.  

Segregation also enhances the diversity in the sense that it could lead to a new ecosystem with a new ecological balance within it. Conservation biologists focus on these areas as they claim that  where the greatest number of unique species can be found and protected with in the large number of reserve areas with the least amount of effort  


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