Answer:
D. 0.60
Explanation:
If the population is in Hardy-Weinberg equilibrium, the genotypic frequencies are:
- freq AA = p²
- freq Aa = 2pq
- freq aa = q²
<em>p</em> is the frequency of the Rh positive allele (A) and <em>q</em> is the frequency of the Rh-negative allele (a).
If 84% of the population is Rh-positive, then 16% is Rh-negative and has the genotype <em>aa</em>. Therefore:
q² = 0.16
q = √0.16
q=0.4
And because p+q=1,
p = 1 - 0.4
p = 0.6
The frequency of the Rh-positive allele is 0.6
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