Answer:
B. Traditional view
Explanation:
the traditional view is that nothing positive results from a conflict
Answer:
Placing salty water in A and distilled water in B.
Explanation:
The fastest net rate of water movement into the A-side will occur if we place salty water on that side and distilled water in the other one. The reason for this is that the A-side contains a higher concentration of solute than B. So, the water will pass the semipermeable membrane and go to the A-side to valance the concentrations on both sides. As we can see, there is an increase in the net rate of water movement into A.
Answer:
If a strand of DNA contains the bases adenine, cytosine, cytosine and guanine the order of the bases on the opposite strand is thymine, guanine, guanine and cytosine.
Explanation:
DNA contains a double strand, each of which contains a specific sequence of bases —adenine, thymine, cytosine and guanine— whose order determines the genetic information stored in this nucleic acid.
The sequence of bases on one DNA strand is complementary on the other strand, taking into account the complementarity of bases, i.e. the purines adenine and guanine are complemented by the pyrimidines thymine and cytosine, respectively:
A = T
G ≡ C
<u>So that the sequence A - C - C - G of one chain is complemented by the sequence T - G - G - C of the other</u>.
<em> Taking into account the above information, the other options can be discarded, as they do not comply with the complementarity of bases in the DNA.</em>
This is the DNA. I'm going to only use the upper strand to demonstrate what this strand would code for before and after a single bp deletion (so write it as mRNA). I will also write it how it's easier to see this which is to split them up into the 3 base codon system. Note that you don't need to know the amino acid code - you use a table to find these.
ORIGINAL (mRNA on top, Amino Acid (AA) on bottom:
5'-AGC GGG AUG AGC GCA UGU GGC GCA UAA CUG-3'
SER GLY MET SER ALA CYS GLY ALA STOP LEU
Note that the protein would stop being made at the stop codon and the LEU wouldn't matter at the end...
Now, I will remove one bp...(I bolded it up top). Rewrite the mRNA and find the corresponding AA...
NEW
5'-AGC GGG AUG GCG CAU GTG GCG CAU AAC UG-3'
SER GLY MET ALA HIS VAL ALA HIS ASN .....
Completely different amino acid sequence after the methionine (MET). The stop codon is gone...the protein would continue being translated until it reaches another stop codon...so not what was supposed to be made!
confirmation bias?
i think that may be correct but i'm not 100% positive i hope it helps a little. Good Luck