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natali 33 [55]
2 years ago
7

How could the duplication of the Hox gene complex help facilitate animal adaptive radiation?

Biology
1 answer:
cestrela7 [59]2 years ago
4 0

Answer:

Duplication of hox genes is important in the radiation of animals because they are regulating genes of symmetry and the body plan of the animals' bodies. Some change or mutation in these genes during duplication can cause mutations and with these evolution of the species as it controls the different segments of these animals as they develop, launching the genetic programs that form various body structures, such as limbs and organs. .

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Given are five km values for the binding of substrates to a particular enzyme. which has the strongest affinity when k–1 is grea
solmaris [256]

Answer;

- 1.2 nM

Explanation;

-Smallest Km means highest affinity, can bind substrate better at lower concentrations. The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate. This is usually expressed as the Km (Michaelis constant) of the enzyme, an inverse measure of affinity

-Km is therefore, the concentration of substrate which permits the enzyme to achieve half Vmax. An enzyme with a high Km has a low affinity for its substrate, and requires a greater concentration of substrate to achieve Vmax.

8 0
2 years ago
Which of the following statements about algorithms is false?
garik1379 [7]
I think that it’s c but I could be wrong!
4 0
2 years ago
The development of artificial blood was fueled by the increased number of HIV cases, threatening an increase in the amount of co
Rufina [12.5K]
The commence is off base with regards to the enthusiasm for creating fake blood. The intrigue is on the grounds that the timeframe of realistic usability of put away blood is extremely constrained. The other intrigue is concerning transfusion responses related with red platelet antigens that can bring about lethal responses and cause delays in finding good blood that hazard understanding lives. At present the rate of securing HIV disease through blood transfusions has been computed to associate with one case for every a million or two million transfusions. That viewpoint has been tackled with respect to testing however alternate issues still remain and they persuade the proceeded with look for simulated blood. Other developing infections like Zika and other obscure infections additionally makes a requirement for such research.
7 0
2 years ago
Read 2 more answers
Determination of Caloric Content of Three Foods1. Compare the calorimeter that you built to a bomb calorimeter. How are they sim
yulyashka [42]

Answer:

The answers to both parts (1 and 2) are given below.

Explanation:

1. The calorimeter is similar to the bomb calorimeter in a way that both measure the changes in heat that occur as result of the chemical reaction taking place inside them. They are different in the sense that a bomb calorimeter provides an isolated system with constant volume and pressure, whereas a regular calorimeter allows pressure to equalize with the environment.

2. Carbohydrates are the molecules that break down and provides energy for cellular functions. Whereas, proteins are not meant for the production of energy but for the production of amino acids to function as structural units for protein synthesis. Simply, the breakdown of protein is for the synthesis of more proteins by providing several units of amino acids rather than the production of energy.

5 0
2 years ago
One polled (hornless) bull is bred to 3 cows. With Cow A, which is horned, a polled calf is produced. With Cow B, also horned, a
Arisa [49]

Answer:

Bull = Pp

Cow A = pp

Cow B = pp

Cow C = Pp

Explanation:

In cows polled (P) is dominant over horned (p) trait.

The bull is polled so it can be PP or Pp. Cow B is horned so it must be pp. Resultant offspring from bull X Cow B is also a horned calf (pp). This calf must have received one p from the bull. So the bull's genotype is Pp.

Cow A is also a horned cow so it must be pp. When bull X Cow A, a polled calf is produced. Since the bull's genotype is Pp and Cow A's genotype is pp, this polled calf will be Pp like the bull.

Cow C is polled like the bull so it can be PP or Pp. However on crossing with the bull (Pp) a horned calf is produced (pp). This calf got one p allele from the bull and p allele from the Cow C. So Cow C's genotype must be Pp.

Hence,

Bull = Pp

Cow A = pp

Cow B = pp

Cow C = Pp

5 0
2 years ago
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