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Ne4ueva [31]
1 year ago
5

Given are five km values for the binding of substrates to a particular enzyme. which has the strongest affinity when k–1 is grea

ter than k2?
Biology
1 answer:
solmaris [256]1 year ago
8 0

Answer;

- 1.2 nM

Explanation;

-Smallest Km means highest affinity, can bind substrate better at lower concentrations. The relationship between rate of reaction and concentration of substrate depends on the affinity of the enzyme for its substrate. This is usually expressed as the Km (Michaelis constant) of the enzyme, an inverse measure of affinity

-Km is therefore, the concentration of substrate which permits the enzyme to achieve half Vmax. An enzyme with a high Km has a low affinity for its substrate, and requires a greater concentration of substrate to achieve Vmax.

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Let's consider a scenario in which the resting membrane potential changes from −70 mv to +70 mv, but the concentrations of all i
Nookie1986 [14]
<span>Let's consider a scenario in which the resting membrane potential changes from −70 mV to +70 mV, but the concentrations of all ions in the intracellular and extracellular fluids are unchanged. Predict how this change in membrane potential affects the movement of Na+. The electrical gradient for Na+ would tend to move Na+ Outside the cell (extracellular) while the chemical gradient for Na+ would tend to move Na+ Inside the cell (intracellular).

The electrical gradient is defined as the + goes to the - and the - goes to the +
Na + has a positive charge, but there's more positive charge inside the cell than outside (due to potassium), therefore, Na+ goes extracellular (out)
The concentration gradient considers that the ion will go from the most concentrated to at least concentrated by passive diffusion so no trans-membrane proteins in the game attention.Na + is very concentrated in extracellular and few intracellular, therefore, it tends to go intracellular (in).</span>
5 0
2 years ago
Ground squirrels are found in many areas of the United States. They live in underground burrows and are often attacked by birds
Ket [755]

The population of the ground squirrels will be limited by the population of the hawks. The population of the hawks, thus, will be a limiting factor for the population of the ground squirrels. The Hawks are the birds of prey that feeds on squirrels. With the increased number of hawks in the same area as them will put these squirrels in danger. The population of the tree squirrels, however, will have no affect on the population of the ground squirrels. The genetic variability and breeding season are not limiting factors for their population either.

Hence, the correct answer is 'option B - a population of hawks'.

4 0
1 year ago
Read 2 more answers
What is the correct term for variation in characteristics within populations of the same species? A variation in characteristics
Crazy boy [7]

Answer:

The correct answer would be phenotypic variation.

Phenotype refers to observable traits or characteristics of an individual. For example, height, color, shape, et cetera.

Phenotypic variation refers to the sum total of variations in characteristics within populations of the same species.

In contrast, genotypic variation refers to the sum total of variations (such as allele frequency) present in the genome of populations of the same species.

5 0
1 year ago
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Describe the immediate effect of the neurotoxin on the number of action potentials in a postsynaptic neuron. Predict whether the
nikdorinn [45]

Answer:

Inhibit control over ions.

Explanation:

The immediate effect of the neurotoxin on the postsynaptic neuron is to inhibit control over ion concentrations across the cell membrane. The neurotoxin blocks nervous transmission at synapses which prevents the vesicles containing the neurotransmitter from fusing with the presynaptic membrane so the information does not transfer from one neuron to another and as a result the body is present at constant relaxation mode. The membrane potential of postsynaptic neuron will decrease due to neurotoxin.

3 0
1 year ago
If sugar is sprinkled on a strawberry, osmosis will cause
Goshia [24]

Answer:

The correct answer is c. water to move out of the strawberry, making it smaller

Explanation:

Osmosis is the process refers to the movement of liquid molecule from the area of high solute concentration to an area of low solute concentration through a semipermeable membrane to equalize the osmotic balance.

Osmosis is important for any cell to maintain a proper osmotic balance of the cell. So if sugar is sprinkled on a strawberry the solute concentration outside the strawberry cells will increase which will result in water release from the cell.

This release of water from the cell will shrink the strawberry and make it small.  Therefore the correct answer is c.

3 0
2 years ago
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