The number of times the spinner landed on a space numbered greater than 4 = 167
Step-by-step explanation:
Step 1 :
Given,
Number of equal area spaces in the spinner = 6
Number of times the spinner was spun = 500
We need to find the number of times the spinner landed on a space numbered greater than 4
Step 2 :
Total number of outcome = 6
Favorable outcomes are = Numbers greater than 4 = 5,6
Total number of favorable outcome = 2
Therefore Probability that the spinner will land on a number that is greater than 4 is
= 
The number of times that the spinner landed on a space numbered greater than 4 = 500 ×
= 166.67 = 167 (rounded off to the nearest integer)
Step 3 :
Answer :
The number of times the spinner landed on a space numbered greater than 4 = 167
Answer:
a(46) = -1.5 + 0.2(45) = -1.5 + 9 = 7.5
Step-by-step explanation:
Each term of this sequence is 0.2 greater than the previous term. The formula for this arithmetic sequence is
a(n) = -1.5 + 0.2(n - 1)
and so the 46th term is:
a(46) = -1.5 + 0.2(45) = -1.5 + 9 = 7.5
I believe it is 7.875. If you want it simplified it would be 8 ounces. Please give me brainliest!