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faltersainse [42]
2 years ago
13

Help!!

Mathematics
2 answers:
Xelga [282]2 years ago
6 0

Answer:

D. 63%

Step-by-step explanation:

the white marble was picked out 41 of the 65 times, so 41/65

divide 41 by 65 in your calculator and you get .6307

then multiply it by 100 because it asked for a percentage and you get 63%

Ta-Da!

Zarrin [17]2 years ago
4 0

Answer:

63%

Step-by-step explanation:

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A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like
mixas84 [53]

Answer:

a) \mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) \mathbf{x = 2000 - 2000e^{-0.015t}}

c)  the  steady state mass of the drug is 2000 mg

d) t ≅ 153.51  minutes

Step-by-step explanation:

From the given information;

At time t= 0

an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500

The inflow rate is 0.06 L/min.

Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.

The objective of the question is to calculate the following :

a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.

From above information given :

Rate _{(in)}= 500 \ mg/L  \times 0.06 \  L/min = 30 mg/min

Rate _{(out)}=\dfrac{x}{4} \ mg/L  \times 0.06 \  L/min = 0.015x \  mg/min

Therefore;

\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}

with respect to  x(0) = 0

\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}

b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.

\dfrac{dx}{dt} = -0.015(x - 2000)

\dfrac{dx}{(x - 2000)} = -0.015 \times dt

By Using Integration Method:

ln(x - 2000) = -0.015t + C

x -2000 = Ce^{(-0.015t)

x = 2000 + Ce^{(-0.015t)}

However; if x(0) = 0 ;

Then

C = -2000

Therefore

\mathbf{x = 2000 - 2000e^{-0.015t}}

c) What is the steady-state mass of the drug in the blood?

the steady-state mass of the drug in the blood when t = infinity

\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}

x = 2000 - 0

x = 2000

Thus; the  steady state mass of the drug is 2000 mg

d) After how many minutes does the drug mass reach 90% of its stead-state level?

After 90% of its steady state level; the mas of the drug is 90% × 2000

= 0.9 × 2000

= 1800

Hence;

\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}

0.1 = e^{(-0.015t)

ln(0.1) = -0.015t

t = -\dfrac{In(0.1)}{0.015}

t = 153.5056729

t ≅ 153.51  minutes

4 0
2 years ago
The HCF of the greatest 2- digit number and the greatest 3-digit number is
Natasha_Volkova [10]

Answer:

9

Step-by-step explanation:

So the greatest 2 digit number is 99 and the greatest 3 digit number is 999

So find the hcf ( highest common factor ) of 99 and 999.

Factors of 99      : 1, 3, 9, 11, 33, 99

Factors of 999    : 1, 3, 9, 27, 37, 111, 333, 999

Common factors : 1, 3, 9

Hcf                       : 9

HOPE IT HELPED

7 0
2 years ago
A tank contains 8000 L of pure water. Brine that contains 35 g of salt per liter of water is pumped into the tank at a rate of 2
OleMash [197]

Answer:

The concentration of salt in the tank approaches 35 \mathrm{g} / \mathrm{L},

Step-by-step explanation:

Data provide in the question:

Water contained in the tank = 8000 L

Salt per litre contained in Brine = 35 g/L

Rate of pumping water into the tank = 25 L/min

Concentration of salt \lim _{t \rightarrow \infty} C(t)=\lim _{t \rightarrow \infty} \frac{35 t}{320+t}

Now,

Dividing both numerator and denominator by t, we have

\lim _{t \rightarrow \infty} \frac{\frac{1}{t} 35 t}{\frac{1}{t}(320+t)}=\lim _{t \rightarrow \infty} \frac{35}{\frac{320}{t}+1}=35

Here,

The concentration of salt in the tank approaches 35 \mathrm{g} / \mathrm{L},

3 0
2 years ago
What value does the 6 represent in the number 240.65
Kobotan [32]

Answer:

000.60

six hundredths

4 0
2 years ago
Is ΔWXZ ≅ ΔYZX? Why or why not? Yes, they are congruent by SAS. Yes, they are both right triangles. No, the triangles share side
gizmo_the_mogwai [7]
I will attached the picture of what you are talking about here. The answer for this problem is: Yes, that they are congruent by SAS. Meaning that the triangles are congruent if their included angles and any pair of corresponding sides are equal in both triangles. In this case, the sides are both 21 cm and this will make the angle equal for both triangles, so that is why they are congruent.

9 0
2 years ago
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