Euglena is green in color because of the chlorophyll that is contained in the chloroplast of that organism and the body structure that is located at its base is known as flagellum
.
Explanation:
Euglena are species that are found in the fresh and salt water. They are abundantly found in inland waters where they manage themselves to bloom in large amount and color the water surface of ditches and ponds green.
This green color which them form are mainly due to the chlorophyll that is contained in the chloroplast of the organism. chlorophyll is known to be the pigment that is responsible for the green color.It is the cause for the green color in this case too.
Euglena contains a specialized body structure which is located at the base of the tail by which it manages to move.
This specialized structure is known as Flagellum.
Bacteria is a unicellular organism which can multiply very fast by binary cell division.
To get a number of divisions required for cell division: you can use the formula: 2
= number of bacteria
To get 256 bacteria:
2
= 256 (you can solve this equation by a calculator)
so:
n = 8 generations
With this formula the first bacteria is taken into consideration since 1 bacteria gives two, then the two give four, then eight, 16...
<span>Let's consider a scenario in which the resting membrane potential changes from −70 mV to +70 mV, but the concentrations of all ions in the intracellular and extracellular fluids are unchanged. Predict how this change in membrane potential affects the movement of Na+. The electrical gradient for Na+ would tend to move Na+ Outside the cell (extracellular) while the chemical gradient for Na+ would tend to move Na+ Inside the cell (intracellular).
The electrical gradient is defined as the + goes to the - and the - goes to the +
Na + has a positive charge, but there's more positive charge inside the cell than outside (due to potassium), therefore, Na+ goes extracellular (out)
The concentration gradient considers that the ion will go from the most concentrated to at least concentrated by passive diffusion so no trans-membrane proteins in the game attention.Na + is very concentrated in extracellular and few intracellular, therefore, it tends to go intracellular (in).</span>
Answer:
Following are the answer to this question:
Explanation:
In option a:
There are many ways, which can be defined as follows:
- It keeping cells "qualified," use heat shock and handle ions like Ca and ice incubating.
- It uses Micro-injection with DNA.
- It uses the biolistics or even the process of gene-gun.
The stable cell charts indicate simple and definitive outcomes when their relationship to specific results. Moreover, relative to temporary cell lines, findings are more reliable and error-free. These lines also easily break and much less.
In option b:
Radio tests including linking tests could be used
The Ligand Binding Assays is an analysis, that is based on the binding of ligands to antibodies, or other macromolecules. Its existence and distance of formed ligand-receptor complexes are defined using a system of measurement that is usually electrical or fluorescent.
In option c:
The method for measuring the levels of cell growth is accessible and the Another way is to measure the metabolism within the same cell. So many color pigments were also accessible that can permeate an organism as well as react with some proteins as well as other factors, and that can effectively identify a color final product.
Throughout relation to the amount of metabolism exercise, cell proliferation could be evaluated by researching one or even more cell markings. The BrdU limited liability assessment is a very well-published illustration.
Its specific antibody can detect BrdU and high BrdUincorporations levels are linked to high levels of cell proliferation. Command cell without DNA receptor growth hormone.
In option d:
The cell growth will stop after each use of RNA interference ( RNAi). The p007 formation as well as the effect on growth caused by the intrusion will be a goal. If development is delayed effectively, the theory will be tested successfully to a cell without any of the required DNA. The RNAi is the free cell
Answer:
Only Photosystem I - 1, 5, 6
Only photosystem II - 3, 2
Both Photosystem I and II - 4
Explanation:
Only Photosystem I
a) Reduction of NADP+ - uses light energy to convert NADP+ to NADPH2
b) Reduction of electron transport chain between the two photosystems
c) Oxidation of electron transport chain between the two photosystems.
Only photosystem II
a) Oxidation of water - here the absorbed light energy is used to dissociate of water molecules to produces protons (H+) and O2 along with free ions
b)Reduction of primary electron acceptor - An electron is taken by pheophytin which is a primary electron acceptor molecule that is located within photosystem II and hence it get reduced.
Both Photosystem I and II
a) Light is absorbed in both photosystem I and II. While in photosystem I, light waves of large wavelength i.e 700 nm are absorbed, in photosystem II light waves of short wavelength of i.e 680 nm are absorbed.
