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kap26 [50]
2 years ago
7

It is common to use ddNTPs (dideoxynucleoside triphosphates) for sequencing DNA because, when incorporated into a growing DNA po

lymer, the ddNTP acts as a chain terminator, allowing the researcher an opportunity to determine the last-added base to a given chain. From your knowledge of nucleotide structure and DNA synthesis, what is the most likely attribute of ddNTPs for DNA sequencing?
A. The ddNTPs lack a 5′ carbon.

B. The ddNTPs lack a 3′ hydroxyl group.

C. The ddNTPs lack a nitrogenous base.

D. The ddNTPs lack the sugar component.
Biology
1 answer:
Aliun [14]2 years ago
4 0

Answer:

B. The ddNTPs lack a 3′ hydroxyl group.

Explanation:

Dideoxynucleotides is a family of inhibitors of the DNA polymerase, its official name is 2',3' dideoxynucleotides but they are commonly called ddNTPs. One of the main characteristics of this compound is the absence of the 3'-hydroxyl group in the deoxyribose, due to the absence of this group, it is impossible to form a phosphodiester bond between nucleotides and the DNA synthesis is stopped.

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Answers;

-The P generation has yellow and green seeds.

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-The F2 generation has yellow and green seeds.

Explanation;

Yellow seed color (dominant)

Green seed color (recessive)

P generation: In Mendel's experiments the parental generation.

Yellow seed color

F1 generation: In Mendel's experiments the offspring of the P generation

Yellow seed color and

Green seed color

F2 generation: In Mendel's experiments the offspring of the F1 generation

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Answer:

At the end of<u> telophase II </u>and cytokinesis, there are four haploid cells.cells.

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We have to remember that there will be four haploid cells because there are two cells, which are the result of meiosis I, that will go into meiosis II to give these four daughters haploid cells. Also, the phases in meiosis I and II are very similar. Both of them have prophase, metaphase, anaphase, and telophase.

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i'm sure is B

Explanation:

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Answer:

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Explanation:

The complex carbohydrates are synthesized by the joining of monosaccharide residues by glycosidic linkages.One glycosidic linkage joins two monosaccharide residues by the elimination of one molecule of water.

  In other words it can be said that elimination of one water molecule joins two monosaccharides.By the same way elimination of 42 molecules of water will result in the joining of 43 monosaccaride residues.

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Some single-celled protists, such as paramecia, live in an extremely hypotonic environment and have contractile vacuoles that
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