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2 years ago

Julia and Tanveer are solving the questions shown in the table.

Mathematics

2 answers:

Kobotan [32]2 years ago

8 0

Answer:

The problem which is best modeled by a division expression is,

A. only Julia's.

Step-by-step explanation:

The problem which is best modeled by a division expression is,

A. only Julia's.

Answer to Julia's problem:-

The number of $\frac {1}{4}$ quart servings which the cooler does hold is given by,

$\frac {8}{\frac {1}{4}}$

= 32

Answer to Tanveer's problem:-\

The number of quarts of juice needed to give 8 people each $\frac {1}{4}$ quart serving of juice is given by,

$(8 \times \frac {1}{4})$

= 2

Over [174]2 years ago

5 0

Answer:

A- Only J

Step-by-step explanation:

Took the test got it right

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Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented

sp2606 [1]

Answer: The answer is $A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Step-by-step explanation: Given that the area of the whole circle is represented by the expression

$A_c=25x^2-12x-9.$

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

$A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Thus, the area of the outer ring is

$A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

5 0

2 years ago

Express 25.6 nanometres in metres, giving your answer in standard form.

zhannawk [14.2K]

Answer:

10 to power of -8 so 0.00000001 I think

8 0

2 years ago

A cement bridge post is 24 inches square and 15 feet 9 inches in length. If the cement weighs 145 pounds per cubic foot, how muc

lisov135 [29]

Answer:

The answer is option (C), One cement bridge post weighs 9,135 pounds

Step-by-step explanation:

Step 1: Get the total volume of a cement bridge post

The cement bridge post is in the shape of a cuboid, therefor the volume of the cement bridge post can be expressed as;

Volume of cement bridge post=Base area×Length

where;

Base area=(24^2) inches square

1 foot=12 inches

Convert 24 inches to foot=24/12=2^2=4 feet²

Length=15 feet and 9 inches

1 foot=12 inches

Convert 9 inches to foot=9/12=0.75 feet

Total length=(15+0.75)=15.75 feet

replacing;

Volume of cement bridge post=(4×15.75)=63 cubic feet

Volume of cement bridge post=63 cubic feet

Step 2: Get the total weight of the cement bridge post

Total weight of the cement bridge post=Weight per cubic foot×total volume of the cement bridge post

where;

Weight per cubic foot=145 pounds per cubic foot

Total volume of the cement bridge post=63 cubic feet

replacing;

Total weight of the cement bridge post=(145×63)=9,135 pounds

One cement bridge post weighs 9,135 pounds

8 0

2 years ago

The dot plots below show the scores for a group of students for two rounds of a quiz: Two dot plots are shown one below the othe

miskamm [114]

Answer:

The inference that can be made using the dot plot is:

The range of round 1 is greater than the round 2 range.

Step-by-step explanation:

<u>Round 1:</u>

Score Frequency

1 0

2 2

3 3

4 2

5 1

Hence, the minimum score of Round 1 is: 2

maximum score is: 5

Hence, Range=Maximum value-Minimum score

=5-2

Similarly, <u>Round-2</u>

Score Frequency

1 0

2 0

3 0

4 4

5 4

Hence, the minimum score of Round 1 is: 4

maximum score is: 5

Hence, Range=Maximum value-Minimum score

=5-4

The scores of round 2 are higher than round-1.

Since round 2 have a higher frequency for higher scores as compared to round-1.

Hence, Range of round 1 is greater than the range of Round-2.

6 0

2 years ago

Read 2 more answers

Estimate each number as a single digit times a power of ten . Drag expressions to complete the table

Crazy boy [7]

Answer:

Concept: Number Analaysis

The first option goes back 9 spaces hence
$4.3 \times {10}^{ - 9}$
Second one you to forward 10 spaces hence
$4.3 \times 10 ^{10}$
Using that logic solve the rest!

7 0

2 years ago