A. are required for the expression of specific protein-encoding genes.
B. bind to other proteins or to a sequence element within the promoter called the TATA box.
C. inhibit RNA polymerase binding to the promoter and begin transcribing.
D. usually lead to a high level of transcription even without additional specific transcription factors.
E. bind to sequences just after the start site of transcription.
Answer: B
Answer:
These plants look so similar because of convergent evolution/analogy.
Explanation:
Analogy in evolution is the development of similar or analogous structures in distantly related species occupying the same environment. This is because the species have developed similar adaptations, over time, which enables them to survive in their environment.
Answer:
c less land available for growing crops
Explanation:
if we use the land for parking lots there will be lees room for farming
there for there will be less food
Answer:
4, 3 5, 1, 2.
Explanation:
The events of muscle contraction begins from the presynaptic neuron, which cause the influx of Ca+, and the release of acetycholine neurotransmitter into the synaptic cleft.
The Ach, binds with the receptors in the sarcolemma, leading to opening of Ligand gated Na+ channels. Therefore Na+diffuses in, causing depolarization, and propagation of action potential along the sarcolemma spreading to the T-tubules.
This is followed by opening of Calcium channels leading exist of Ca+ from the sarcoplasmic reticulum.
The Calcium binds with the troponin, and Tropomysoin exposed the myosin binding sites on the actin filament.Thus cross-bridge is formed by the myosin head with thin filaments which shortened the sarcomere, leading to contraction of muscle fibres.
Answer:
36
Explanation:
A two-point test-cross is a cross between an individual with a double heterozygote genotype and a homo-zygous recessive individual in order to determine the recombination frequency between two linked genes. In genetics, one map unit (m.u.) can be defined as the measure of the distance (i.e., genetic distance instead of physical distance) between genes for which one (1) product of meiosis in one hundred (100) is recombinant. In this case, 36 of the offspring have the recombinant phenotype, while the remaining 64 offspring are not recombinant, and therefore both genes are separated by 36 mu (64 + 36 = 100 >> 36 mu).
