Answer:
The first male was bb Ee, and the second male was bb EE.
Explanation:
In Labradors coat colour is controlled by two genes. Suppose the two genes are B and E. B produces black colour and recessive form bb gives brown colour. Gene E is epistatic over gene B in its recessive form which means that ee will produce yellow colour regardless of the genotype present of B gene.
The first case is possible if the female lab is bbee (yellow) and the male lab is bbEe (brown):
bbee X bbEe
bE be
be bbEe bbee
So half of the offspring will be brown (bbEe) and half of them will be yellow (bbee)
The second case is possible if the same female bbee mates with a brown male of different genotype which can be bbEE:
bbee X bbEE
bE
be bbEe
So all offspring will be brown (bbEe)
Hence, the first male was bbEe and the second male was bbEE.
Answer:
Option (A)
Explanation:
Fungus are the unicellular eukaryotic living organisms that are so small that it cannot be seen with our naked eye. It plays a significant role in decomposing the dead plants, animals, and other organic matters. They are present in both terrestrial as well as the aquatic environment.
<u>Fungus are most closely related to the animals</u>, because they both have similar characteristics.
Fungus cannot prepare their own food like animals and they are considered to be heterotrophic. They can reproduce by the means of spores and their cells are comprised of nuclei with various numbers of chromosomes. These are the first unicellular organisms on earth from which the evolutionary processes has taken place and formed the present day complex multi-cellular organisms.
Thus, the correct answer is option (A).
Hey hi your answer would be A<span> glycolysis </span>
<em>both producers and consumers are the part of ecosystem but finally either directly or indirectly they become food of the decomposers that may be micro-organisms or the larger parasite or saprophyte ..
organisms taking food from living host are parasite while taking food from dead matter are saprophytes..</em>
Correct answer: "<span>0 homozygous black (bb): 1 heterozygote (black) (bb): 1 homozygous orange "
By crossing a </span><span>heterozygous black-eyed individual (one dominant allele and one recessive allele) with a homozygous orange-eyed individual (only recessive alleles), the possible combinations of the gametes from each individual will lead to the ever presence of a recessive allele (the only one that is passed from the homozygous recessive parent) in the offspring, and either a dominant allele or a recessive allele from the heterozygous parent. So, the outcome offspring will either be heterozygous (with a dominant allele from the heterozygous parent) or homozygous recessive (with a recessive allele from the heterozygous parent). It is impossible to form homozygous dominant individuals from this crossing.
So, the resultant genotypic ratio from this crossing is 0 homozygous dominant:1 heterozygous:1 homozygous recessive.</span>
