Answer:
The conclusion that both groups of overweight and non - overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Step-by-step explanation:
Inferential statistics is simply a type of research statistic whereby a generalized conclusion is made about a larger group based on representative observations
Now,in the given question, we see that both group hearts were above the minimum recommended for cardiovascular exercise. Now we can infer that the DDR games played by both groups gave them cardiovascular benefits. This conclusion is an example of Inferential statistics where we generalize about a large population based on observations from a small sample.
Thus the conclusion that both groups of overweight and non-overweight got cardiovascular benefit from playing DDR games requires Inferential statistics.
Answer:
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}3&1\\4&-2\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The general matrix representation for this transformation would be:
![\left[\begin{array}{cc}x&y\end{array}\right] * A = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
As the matrix A should have the same amount of rows as columns in the firs matrix and the same amount of columns as the result matrix it should be a 2x2 matrix.
![\left[\begin{array}{cc}x&y\end{array}\right] * \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}3x+4y&x-2y\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%2A%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Da%26b%5C%5Cc%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3x%2B4y%26x-2y%5Cend%7Barray%7D%5Cright%5D)
Solving the matrix product you have that the members of the result matrix are:
3x+4y = a*x + c*y
x - 2y = b*x + d*y
So the matrix A should be:
![\left[\begin{array}{cc}3&1\\4&-2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%5C%5C4%26-2%5Cend%7Barray%7D%5Cright%5D)
4⅚ ≥ x; subtract fifty-eight from both sides, divide by -12 from both sides, and you will have your answer.
NOTE: This is where you reverse your inequality symbol [dividing or multiplying by a negative].
Answer:
0
Step-by-step explanation:
We have the fraction
Step 1. Use LCM of the fraction, (2m+3)(2m-3), to simplify the fraction:
![\frac{(2m-3)(2m)-(2m+3)(2m)}{(2m+3)(2m-3)} =\frac{2m^2-6m-[2m^2+6m]}{(2m+3)(2m-3)} =\frac{2m^2-6m-2m^2-6m}{(2m+3)(2m-3)} =\frac{-12m}{(2m+3)(2m-3)}](https://tex.z-dn.net/?f=%5Cfrac%7B%282m-3%29%282m%29-%282m%2B3%29%282m%29%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-%5B2m%5E2%2B6m%5D%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B2m%5E2-6m-2m%5E2-6m%7D%7B%282m%2B3%29%282m-3%29%7D%20%3D%5Cfrac%7B-12m%7D%7B%282m%2B3%29%282m-3%29%7D)
Step 2. Equate the resulting fraction to zero and solve for
:

![-12m=0[(2m+3)(2m-3)]](https://tex.z-dn.net/?f=-12m%3D0%5B%282m%2B3%29%282m-3%29%5D)



Step 3. Replace the value in the original equation and check if it holds:


Since
,


Since the only solution of the equation holds, the equation bellow doesn't have any extraneous solution
The time it takes to install 1 insulator would be 1.25 hours