Answer:
The depreciation expense for year 1 is $16,000
Explanation:
Depreciation: The depreciation was occurred due to tear and wear, obsolesce, time period, etc
Under the straight-line method, the depreciation should be charged with the same amount over the useful life.
The calculation is shown below:
= 
= 
= $16,000
The depreciation should be charged for $16,000 in year 1. Moreover, it is shown in the income statement in the debit side and in the cash flow statement also.
Answer:
Present value of the offer = $739,018.03
Explanation:
The cash flows described in the question from end of year 1 to end of year 20 represent a growing annuity for 20 years. The present value of a growing annuity is calculated as follows:
PV= ![\frac{P}{i-g}*[1-[\frac{1+g}{1+i}]^n]](https://tex.z-dn.net/?f=%5Cfrac%7BP%7D%7Bi-g%7D%2A%5B1-%5B%5Cfrac%7B1%2Bg%7D%7B1%2Bi%7D%5D%5En%5D)
where P = the annuity payment in the first period
i = interest rate per period that would be compounded for each period
g = growth rate
n = number of payment periods
P in the 1st year = the base salary of $59,000 + the 10% bonus of $5,900 = $64,900; g is 3.9% ;i=0.1 and n = 20
Present value of the offer = 15,000 received immediately + PV of the growing annuity
=
=739,018.03
Answer:
The answer is: 5 hours 20 minutes; 4 Trucks
Explanation:
Each truck has a 16 minute window to pick up and dump the coal. This process can be observed as an assembly line where each stage of production is the stages of coal transport. When Truck A is travelling to the dump site, Truck B can be loading the coal. When Truck B is travelling to the dump site and Truck A is dumping the coal, Truck C would be loading the coal. When Truck A is travelling to the loading area, Truck B dumping the coal and Truck C travelling to the dump site, Truck D would be loading the coal. Once Truck A gets to the loading area, Truck D would be on its way to the dump site and so on. In each 16 minute window 88 tons of coal (22 tons * 4) is picked up and dumped, that is, 22 tons every 4 minutes. Given that there are 1, 760 tons of coal, the total time taken to dump all the coal is equal to 320 minutes:
88 tons = 16 minutes (22 tons dumped every 4 minutes)
1, 760 tons = (1760 tons * 16)/88 tons = 320 minutes
320 minutes/ 60 minutes = 5 hours 20 minutes
Answer:
Explanation:
Arrival rate = 40 people per minute
Service rate = 5 seconds per person = 12 people per minute
b) Customer Inflow (Arrival) Rate (Ri)
Ri = Arrival Rate = 40 per minute
Inter arrival Time = 1 / Ri = 1 / 40 minutes
c) Total Processing Rate (Capacity) (Rp)
Processing Time = Tp = 5 seconds =
5/60 minutes
= 1/12 minutes
Processing Rate = Rp = 1 / Tp = 1 / (1/12) = 12 customers per minute
Server utilization = Throughput Rate R / Rp
Chi = Lambda / Miu ( must be < 1 )
Ls = Chi / (1-Chi)
Lq = Ls - Chi
Ws = Ls / Lambda
Wq = Lq / Lambda
Buffer capacity K = 50