Ask question

Ask question

All categories

kondor19780726 [428]

2 years ago

10

Which relationships within the diagram are true? Check all that apply. △ACF ≅ △AEB because of ASA. △ACF ≅ △AEB because of SAS. △

ACF ≅ △AEB because of AAS. ∠CFA ≅ ∠EBA FC ≅ BE FC ≅ AC

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:

The correct answer is (A) △ACF ≅ △AEB because of ASA. (D) ∠CFA ≅ ∠EBA (E) FC ≅ BE

Step-by-step explanation:

∠CAF ≅ ∠EAB, Given that the angle AC ≅ AE; ∠ACD ≅ ∠AED, because is the same angle in Vertex A

Then we say, △ACF ≅ △AEB because of ASA has a coherent side (AC ≅ AE) and the two adjoining angles to this side are also coherent (∠ACD ≅ ∠AED and ∠CAF ≅ ∠EAB), then we say option (A) is true: △ACF ≅ △AEB because of angle side angle.

If the two triangles are coherent, then the FC ≅ BE; and ∠CFA ≅ ∠EBA, by CPCTC, then Options D and E are correct

Maksim231197 [3]2 years ago

7 0

Answer:

a, d , e

Step-by-step explanation:

You might be interested in

A Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer; a sample

8090 [49]

Answer:

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given first random sample size n₁ = 500</em>

Given Roper survey reported that 65 out of 500 women ages 18-29 said that they had the most say when purchasing a computer.

<em>First sample proportion </em>

<em> </em> $p^{-} _{1} = \frac{65}{500} = 0.13$

<em>Given second sample size n₂ = 700</em>

<em>Given a sample of 700 men (unrelated to the women) ages 18-29 found that 133 men said that they had the most say when purchasing a computer.</em>

<em>second sample proportion </em>

<em> </em> $p^{-} _{2} = \frac{133}{700} = 0.19$

<em>Level of significance = α = 0.05</em>

<em>critical value = 1.96</em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>Null hypothesis : H₀: There is no significance difference between these proportions</em>

<em>Alternative Hypothesis :H₁: There is significance difference between these proportions</em>

<em>Test statistic </em>

<em></em> $Z = \frac{p_{1} ^{-}-p^{-} _{2} }{\sqrt{PQ(\frac{1}{n_{1} } +\frac{1}{n_{2} } )} }$ <em></em>

<em>where </em>

<em> </em> $P = \frac{n_{1} p^{-} _{1}+n_{2} p^{-} _{2} }{n_{1}+ n_{2} } = \frac{500 X 0.13+700 X0.19 }{500 + 700 } = 0.165$ <em></em>

<em> Q = 1 - P = 1 - 0.165 = 0.835</em>

<em></em> $Z = \frac{0.13-0.19 }{\sqrt{0.165 X0.835(\frac{1}{500 } +\frac{1}{700 } )} }$ <em></em>

<em>Z = -2.76</em>

<em>|Z| = |-2.76| = 2.76 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected at 0.05 level of significance</em>

<em>Alternative hypothesis is accepted at 0.05 level of significance</em>

<u><em>Conclusion:</em></u><em>-</em>

<em>There is there is a difference between these proportions at α = 0.05</em>

3 0

2 years ago

Complete the steps for solving 7 = –2x2 + 10x. Factor out of the variable terms. inside the parentheses and on the left side of

Mamont248 [21]

we have

$7=-2x^{2} +10x$

Factor the leading coefficient

$7=-2(x^{2} -5x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$7-12.50=-2(x^{2} -5x+2.5^{2})$

$-5.50=-2(x^{2} -5x+2.5^{2})$

Divide both sides by $-2$

$2.75=(x^{2} -5x+2.5^{2})$

Rewrite as perfect squares

$2.75=(x-2.5)^{2}$

Taking the square roots of both sides (square root property of equality)

$x-2.5=(+/-)\sqrt{2.75}$

Remember that

$\sqrt{2.75}=\sqrt{\frac{11}{4}}= \frac{\sqrt{11}}{2}$

$x-2.5=(+/-)\frac{\sqrt{11}}{2}$

$x=2.5(+/-)\frac{\sqrt{11}}{2}$

$x=2.5+\frac{\sqrt{11}}{2}=\frac{5+\sqrt{11}}{2}$

$x=2.5-\frac{\sqrt{11}}{2}=\frac{5-\sqrt{11}}{2}$

<u>the answer is</u>

The solutions are

$x=\frac{5+\sqrt{11}}{2}$

$x=\frac{5-\sqrt{11}}{2}$

5 0

2 years ago

Read 2 more answers

Amanda and Alexis live 4 miles apart. They decide to start walking toward each other’s houses at the same time. Amanda walks at

pishuonlain [190]

Answer:

t = 0.53 hr

Step-by-step explanation:

We write expressions for the distances walked by these two people, sum them up and set the sum equal to 4 miles:

(3.5 mph)(t) + (4mph)(t) = 4 mi

Combining these terms:

(7.5 mph)(t) = 4 mi

4 mi

Solving for t: t = ---------------- = 0.53 hr

7.5 mph

5 0

1 year ago

Ken has 7 baseballs. Each baseball weighs 0.3 pound . Ken wants to use this model to find the total weight of the baseballs. Eac

Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Given that,

Ken has 7 base ball

And each base ball have a weight of 0.3 pounds

If 1 ball = 0.3 pounds

Then, 7 baseball = 7 × 0.3 pounds

So, 7 baseball = 2.1 pounds

Then, the total weight of the 7base balls is 2.1 pounds

But, we want to to use the box to represent this data following the given information in the attachment

Note: since, the weight of the baseball is in decimal points

Let 0.1 pounds be 1 Square box.

Answer

1. To represent the weight of one base ball (0.3 pounds), ken should shade 3 Square box.

Since 1 pounds is 1 Square box

2. To represent the weight of all the seven base ball (2.1pounds), he should shade this amount seven times.

This means that he need to shade 3 square box seven times. This shows that the amount used in the second part of the question means by how much must the square be shaded compare to question the first part of the question

3. The shaded part of the model will represent the expression 0.3 × 7

4. The total weight of the base ball is 2.1 pounds.

3 0

2 years ago

Read 2 more answers

A and B are n×n matrices. Check the true statements below: A. (detA)(detB)=detAB. B. The determinant of A is the product of the

Rudik [331]

Answer with Step-by-step explanation:

We are given that

A and B are matrix.

A.We know that for two square matrix A and B

Then, $det(AB)=det(A)\cdot det(B)$

Therefore, it is true.

B. det A is the product of diagonal entries in A.

It is not true for all matrix.It is true for upper triangular matrix.

Hence, it is false.

C. $\lambda+5=0$

$\lambda=-5$

When is a factor of the characteristics polynomial of A then -5 is an eigenvalue of A not 5.

Hence, it is false.

D.An elementary row operation on A does not change the determinant.

It is true because when an elementary operation applied then the value of matrix A does not change.

8 0

2 years ago