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2 years ago

Which of the functions graphed below could be defined by a cubic equation?

Mathematics

1 answer:

alisha [4.7K]2 years ago

3 0

Answer:

The first graph.

Step-by-step explanation:

I can see 3 graphs. The first one is a cubic equation.

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Credit cards place a three-digit security code on the back of cards. What is the probability that a code starts with the number

ohaa [14]

Answer: 1/10

Step-by-step explanation: because there are 10 numbers (1,2,3,4,5,6,7,8,9, and 0)

7 0

2 years ago

Tags are placed to the left leg and right leg of a bear in a forest. Let A1 be the event that the left leg tag is lost and the e

Komok [63]

Answer:

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, then:

$P(A \cap B) = P(A)*P(B)$

Conditional probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: At least one tag is lost

Event B: Exactly one tag is lost.

Each tag has a 40% = 0.4 probability of being lost.

Probability of at least one tag is lost:

Either no tags are lost, or at least one is. The sum of the probabilities of these events is 1. Then

$p + P(A) = 1$

p is the probability none are lost. Each one has a 60% = 0.6 probability of not being lost, and they are independent. So

p = 0.6*0.6 = 0.36

Then

$P(A) = 1 - p = 1 - 0.36 = 0.64$

Intersection:

The intersection between at least one lost(A) and exactly one lost(B) is exactly one lost.

Then

Probability at least one lost:

First lost(0.4 probability) and second not lost(0.6 probability)

First not lost(0.6 probability) and second lost(0.4 probability)

$P(A \cap B) = 0.4*0.6 + 0.6*0.4 = 0.48$

Find the probability that exactly one tag is lost, given that at least one tag is lost (write it up to second decimal place).

$P(B|A) = \frac{0.48}{0.64} = 0.75$

0.75 = 75% probability that exactly one tag is lost, given that at least one tag is lost

8 0

2 years ago

You are purchasing books summer reading for $4.50 each. Part A: Your total cost, C, depends on,The input is,and the output is,Pa

Crazy boy [7]

Answer:

Part A) see the explanation

Part B) $C(12)=\$54$

Step-by-step explanation:

Part A)

we know that

A relationship between two variables, x, and C, represent a proportional variation if it can be expressed in the form $k=\frac{C}{x}$ or $C=kx$

Let

C ---> is the total cost (represent the output or dependent variable)

x ----> is the number of books (represent the input or independent variable)

In this problem

we have a proportional relationship between the variables x and C

Part B) we know that

The linear equation is given by

$C=kx$

The constant of proportionality k is the same that the slope or unit rate of the linear equation

In this problem the constant k is given

$k=\$4.50\ per\ book$

$C=4.50x$

For x=12 books

substitute in the equation and solve for C

$C=4.50(12)=\$54$

In function notation

$C(12)=\$54$

5 0

2 years ago

Anja is creating a triangle using three straws. The two shorter straws have lengths of 20 cm and 21 cm. How long, in centimeters

Digiron [165]

A^2 + b^2 = c^2...a and b are the legs and c is the hypotenuse
20^2 + 21^2 = c^2
400 + 441 = c^2
841 = c^2
sqrt 841 = c
29 = c <== third straw will be 29 cm

3 0

2 years ago

Find a single expression that represents the area of the outer ring of the circle if the area of the whole circle is represented

sp2606 [1]

Answer: The answer is $A_o=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Step-by-step explanation: Given that the area of the whole circle is represented by the expression

$A_c=25x^2-12x-9.$

We are to find the area of the outer ring of the circle, i.e., to find the circumference of the circle.

Now, if 'r' represents the radius of the circle, then we have

$A_c=\pi r^2\\\\\Rightarrow \dfrac{22}{7}r^2=25x^2-12x-9\\\\ \Rightarrow r^2=\dfrac{7}{22}(25x^2-12x-9)\\\\\Rightarrow r=\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

Thus, the area of the outer ring is

$A_o=2\pi r=2\pi\sqrt{\dfrac{7}{22}(25x^2-12x-9)}.$

5 0

2 years ago