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jonny [76]
2 years ago
13

Which of the functions graphed below could be defined by a cubic equation?

Mathematics
1 answer:
alisha [4.7K]2 years ago
3 0

Answer:

The first graph.

Step-by-step explanation:

I can see 3 graphs. The first one is a cubic equation.

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Devon purchased a new car valued at $16,000 that depreciated continuously at a rate of 35%. Its current value is $2,000. The equ
77julia77 [94]

Answer:

Step-by-step explanation:

Use the equation 2,000 = 16,000(1-r)^t to solve for t;

2000 = 16000(1-0.35)^t

Divide both sides by 16000

2000/16000 = 0.65^t

0.125 =0.65^t

Introduce logarithm on both sides;

<em>ln</em> 0.125 = t <em>ln</em> 0.65

Divide both sides by <em>ln</em> 0.65;

(<em>ln</em> 0.125) / (<em>ln</em> 0.65) = t

-2.07944/ -0.4308 = t

4.827 = t

t= 5 (as a whole number)

Therefore, the car is about 5 years old.

5 0
1 year ago
A machine can stamp 75 caps per minute. At this rate how long will it take to stamp 3000?
Leya [2.2K]
<h2>Answer:</h2><h2>40 minutes</h2>

Step-by-step explanation:

75- caps ----------- 1 minute\\3000 caps ------------x - minutes\\\\Cross-Multiply\\75x = 3000 \times 1\\75x = 3000\\\frac{75}{75} =\frac{3000}{75} \\\\x = 40 minutes

6 0
2 years ago
Read 2 more answers
A baker needs 8 1/2 cups of flour for a sheet cake recipe. He has 4 2/3 cups of flour in a canister and buys 5 1/4 cups more.
Juli2301 [7.4K]

Answer: 1 5/12 cups of flour leftover

Step-by-step explanation: First, add 4 2/3 + 5 1/4. This gives you 9 11/12. 9 11/12 - 8 1/2 = 1 5/12.

6 0
1 year ago
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
1 year ago
Read 2 more answers
Which number in the monomial 215x18y3z21 needs to be changed to make it a perfect cube?
Murljashka [212]
Remember
xyz=(x)(y)(z)
if x and y and z are all perfect cubes, xyz is also a perfect cube

remmeber
(x^n)^m=x^(mn)
so if it is perfect cube it can be factored into
(x^n)^3, such taht n is a whole number
basiclaly, see if the expoent is divisble by 3

all of them should be perfect cubes

215x^18y^3z^21

split them up to see which ones need changing

215=5*43, not  a perfect cube
could be changed to 6^3, which is 216

x^18=(x^6)^3

y^3=y^3
z^21=(z^7)^3

the 215 needs to be changed
 
8 0
2 years ago
Read 2 more answers
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