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dezoksy [38]
2 years ago
14

At a town hall meeting, 37/50 of the members are present. Of those who are present, 1/2 vote in favor of a new park. What fracti

on of the members do not vote in favor of the new park?​
Mathematics
1 answer:
icang [17]2 years ago
8 0

Answer:17.5

Step-by-step explanation:

Half 37

Put into decimal

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MISSY SAYS THAT 5/6 EQUALS 6 DIVIED 5 IS SHE CORRECT? WHY ORWHY NOT.
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It’s 5 divided by 6 bc the 5 is the numerator, no she is not correct.
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Anyone know the answer??
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No. no i do not so yeah.
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Consider a single spin of the spinner.
alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed.  These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0
2 years ago
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What are the real zeros of the function g(x) = x^3 + 2x^2 − x − 2?
PSYCHO15rus [73]
If there are real roots to be found for this polynomial, the Rational Root Theorem and synthetic division are the best way to find them. I teach from a book that uses c and d for the possible roots of the polynomial.  C is our constant, 2, and d is the leading coefficient, 1.  The factors of 2 are +/- 1 and +/-2.  The factors for 1 are +/-1 only.  Meaning, in all, there are 4 possibilities as roots for this polynomial.  But there are only 3 total (because our polynomial is a third degree), so we have to find the first one, at least, from our possibilities above.  Let's try x = -1, factor form (x + 1).  If there is no remainder when we do the synthetic division, then -1 is a root.  Put -1 outside the "box" and the coefficients from the polynomial inside: -1  (1  2  -1  -2).  Bring down the first coefficient of 1 and multiply it by the -1 outside to get -1.  Put that -1 up under the 2 and add to get 1.  Multiply 1 times the -1 to get -1 and put that -1 up under the -1 and add to get -2.  -1 times -2 is 2, and -2 + 2 = 0.  So we have our first root of (x+1).  The numbers we get when we do the addition along the way are the coefficients of our new polynomial, the depressed polynomial (NOT a sad one cuz it hates math, but a new polynomial that is one degree less than that of which we started!).  The new polynomial is x^{2} +x-2=0.  That can also be factored to find the remaining 2 roots.  Use standard factoring to find that the other 2 solutions are (x+2) and (x-1).  Our solutions then are x = -2, -1, 1, choice B from above.
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The number of acres in a region cleared for farming follows the formula a = f (t) = 2t2 where t is the number of months since th
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we are given

a=f(t)=2t^2

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Here, we are given from t=1 to t=4

so, we will get formula as

A=\frac{f(4)-f(1)}{4-1}

now, we can plug values

A=\frac{2(4)^2-2(1)^2}{4-1}

now, we can simplify it

A=10

the average rate of change in the number of acres cleared for farming between t = 1 and t = 4  is 10 acres/ month.............Answer

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