15% of customers that come to your truck order

Carly owns a T-shirt shop. She pays $2.25 for each shirt.

diamong [38]

Answer:

Total number of T-shirts= 200

Cost per T-shirt (without shipping ) = $2.80

Shipping cost per t-shirt ; 5% of a T-shirt = 0.05 *2.80 = $0.14

Total cost of T-shirt (shipping included) = 2.80 +0.14 = $2.94

Markup = 150% of total cost = 1.50 * 2.94 = $4.41

To get the price at which Michelle will sell each T-shirt , add total cost to the markup; 2.94 +4.41 = 7.35.

Therefore, selling price will be $7.35

3 0

2 years ago

What is the length of AC ? 3ft 4ft 9ft 18ft

WINSTONCH [101]

ΔACB and ΔMNB are similar. Therefore the corresponding sides are in proportion:

$\dfrac{AC}{MN}=\dfrac{CB}{NB}\\\\MN=9\ ft\\CB=2\cdot3\ ft=6\ ft\\NB=3\ ft$

Substitute:

$\dfrac{AC}{9}=\dfrac{6}{3}\\\\\dfrac{AC}{9}=2\ \ \ \ |\cdot9\\\\AC=18\ ft$

5 0

2 years ago

A real estate agent sells two sites for Rs. 18000 each. On one he gains 25% and on the other he loses 25 %. What is his loss or

lidiya [134]

HOPE THIS WILL HELP YOU

3 0

2 years ago

g Assume that the distribution of time spent on leisure activities by adults living in household with no young children is norma

OLga [1]

Answer:

"The probability that the amount of time spent on leisure activities per day for a randomly selected adult from the population of interest is less than 6 hours per day" is about 0.8749.

Step-by-step explanation:

We have here a random variable that is normally distributed, namely, the time spent on leisure activities by adults living in a household with no young children.

The normal distribution is determined by two parameters: the population mean, $\\ \mu$ , and the population standard deviation, $\\ \sigma$ . In this case, the variable follows a normal distribution with parameters $\\ \mu = 4.5$ hours per day and $\\ \sigma = 1.3$ hours per day.

We can solve this question following the next strategy:

Use the cumulative standard normal distribution to find the probability.
Find the z-score for the raw score given in the question, that is, x = 6 hours per day.
With the z-score at hand, we can find this probability using a table with the values for the cumulative standard normal distribution. This table is called the standard normal table, and it is available on the Internet or in any Statistics books. Of course, we can also find these probabilities using statistics software or spreadsheets.

We use the standard normal distribution because we can "transform" any raw score into standardized values, which represent distances from the population mean in standard deviations units, where a positive value indicates that the value is above the mean and a negative value that the value is below it. A standard normal distribution has $\\ \mu = 0$ and $\\ \sigma = 1$ .

The formula for the z-scores is as follows

$\\ z = \frac{x - \mu}{\sigma}$ [1]

Solving the question

Using all the previous information and using formula [1], we have

x = 6 hours per day (the raw score).

$\\ \mu = 4.5$ hours per day.

$\\ \sigma = 1.3$ hours per day.

Then (without using units)

$\\ z = \frac{x - \mu}{\sigma}$

$\\ z = \frac{6 - 4.5}{1.3}$

$\\ z = \frac{1.5}{1.3}$

$\\ z = 1.15384 \approx 1.15$

We round the value of z to two decimals since most standard normal tables only have two decimals for z.

We can observe that z = 1.15, and it tells us that the value is 1.15 standard deviations units above the mean.

With this value for z, we can consult the cumulative standard normal table, and for this z = 1.15, we have a cumulative probability of 0.8749. That is, this table gives us P(z<1.15).

We can describe the procedure of finding this probability in the next way: At the left of the table, we have z = 1.1; we can follow the first line on the table until we find 0.05. With these two values, we can determine the probability obtained above, P(z<1.15) = 0.8749.

Notice that the probability for the z-score, P(z<1.15), of the raw score, P(x<6) are practically the same, $\\ P(z$ . For an exact probability, we have to use a z-score = 1.15384 (without rounding), that is, $\\ P(z$ . However, the probability is approximated since we have to round z = 1.15384 to z = 1.15 because of the use of the table.

Therefore, "the probability that the amount of time spent on leisure activities per day for a randomly selected adult from the population of interest is less than 6 hours per day" is about 0.8749.

We can see this result in the graphs below. First, for P(x<6) in $\\ N(4.5, 1.3)$ (red area), and second, using the standard normal distribution ( $\\ N(0, 1)$ ), for P(z<1.15), which corresponds with the blue shaded area.

5 0

2 years ago

Which equation represents the volume of a cone with the same base and height as the cylinder below? A cylinder with a height k a

Igoryamba

Answer: The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation: The first important detail to note here is that both cylinder and cone have the same base and the same height This implies that when writing out the formula for calculating the volume of either of the two shapes, the radius and the height will be the same number or value.

The volume of a cylinder is given as;

Volume cylinder = pi x r squared x h (that is πr²h)

Also the volume of a cone is given as;

Volume cone = one-third x pi x r squared x h (that is 1/3*πr²h)

However, the variables have been changed such that the radius r is now represented by t while the height h is now represented by k.

Therefore the volume of the cone should now be re-written as;

Volume cone = one-third pi t squared k (that is 1/3 *πt²k)

3 0

2 years ago

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