I'll just show you how to make a frequency table using the above data.
We will group the data into class intervals and determine the frequency of the group.
<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17
Let us assign a class interval of 20.
Class Interval Tally Frequency
0-20 8, 12, 4, 18, 9, 5
21-40 25, 32, 39, 36, 33 5
41-60 45, 50, 67 3
61-80 62, 73, 80 3
81-100 99 1
That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
1=28:40 I don't know about the rest
I am not sure about this but here goes nothing: d=2.5t+2.2 is very familiar to y=mx+b y=d m=2.5 x=t b=2.2 to find a new quasion we substitute d and t into place wich equals 1=2.5(0)+b simplification and you get b=1 so your answer is d=2.5t+1
Answer:
Step-by-step explanation:
Let A = Adam, B = Betty
Adam and Betty purchased a printer together for $258.
This means we can say A + B = 258.
We are also told Adam paid $18 less than twice Betty.
You can write this as:
Adam = 2 x Betty - 18
A = 2B - 18
Substitute "A" into the A + B equation and you get:
A + B = 258
2B - 18 + B = 258
3B - 18 = 258
Add 18 to both sides.
3B = 258 + 18
3B = 276
Divide both sides by 3 to find B
B = 276/3 = 92 (This means Betty paid $92).
Since the total that they paid together was $258.
This means Adam pays the Total - How much Betty paid
Adam = 258 - 92 = $166
Add up all sides lengths:
s+6 + s+6 + s + s + 2s = 102
solve for s:
6s + 12 = 102
6s = 90
s= 15
The lengths of sides are as follows:
15, 21, 21, 15, 30 inches
I hope that
helps!
