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svp [43]
2 years ago
10

Suppose you are titrating an acid of unknown concentration with a standardized base. At the beginning of the titration, you read

the base titrant volume as 2.94 mL. After running the titration and reaching the endpoint, you read the base titrant volume as 16.47 mL. What volume of base was required for the titration?
Chemistry
1 answer:
Dvinal [7]2 years ago
6 0

Answer:

The volume of base was required for the titration is 13,53mL

Explanation:

In a titration of an acid (HX) with a base (YOH), the reaction of neutralization is:

HX + YOH → YX + H₂O

In the burette you are adding base until all HX reacts. The addition of base is in volume.

If in the beginnig, the volume that you read of base is 2,94mL and at the endpoint you read a volume of 16,47mL. The volume you spent in the titration that is the same volume of base you required for the titration is:

16,47mL - 2,94mL = <em>13,53mL</em>

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I hope it helps!

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Pure platinum is too soft to be used in jewelry because it scratches easily. To increase the hardness so that it can be used in
Zina [86]

Answer:

percentage mass of platinum in the alloy ≈ 90.60 %

Explanation:

The alloy is 8.528 g sample of an alloy containing platinum and cobalt . The alloy react with excess nitric acid to form cobalt(ii) nitrate . Platinum is resistant to acid so it will definitely not react with the acid only the cobalt metal in the alloy will react with the acid.

The chemical reaction can be represented as follows:

Co (s) + HNO₃ (aq) → Co(NO₃)₂ (aq) +  NO₂ (l) + H₂O (l)

The balanced equation

Co (s) + 4HNO₃ (aq) → Co(NO₃)₂(aq) + 2NO₂ (l) + 2H₂O (l)

Cobalt is the limiting reactant

atomic mass of cobalt = 58.933 g/mol

Molar mass of Co(NO₃)₂ = 58.933 + 14 × 2 + 16 × 6 = 58.933 + 28 + 96 = 182.933  g

58.933 g of cobalt produce 182.933  g of  Co(NO₃)₂

? gram of cobalt will produce 2.49 g of Co(NO₃)₂

cross multiply

grams of cobalt that will react = (58.933 × 2.49)/182.933

grams of cobalt that will react = 146.74317000/182.933

grams of cobalt that will react= 0.8021689362 g

grams of cobalt that will react = 0.802 g

mass of platinum in the alloy  = 8.528 g - 0.802 g = 7.726 g

percentage  mass of platinum in the alloy = 7.726/8.528 × 100 = 772.600/8.528 = 90 .595 %

percentage mass of platinum in the alloy ≈ 90.60 %

6 0
2 years ago
Determine the number of moles of KOH present in 95.0 ml of 0.255 M solution​
gizmo_the_mogwai [7]

Answer:

Moles of KOH in 1000 mL solution = 0.255 moles

Moles of KOH in 1 mL solution = 0.255/1000 = 0.000255 moles

Moles in 95 mL solution = (95 * 255)/1000000 = 24225/1000000

Moles of KOH in 95 mL 0.255M solution = 0.024225 moles

6 0
2 years ago
Under which conditions will sugar most likely dissolve fastest in a cup of water? A. a sugar cube with stirring at 5oC B. a suga
OverLord2011 [107]
I believe the answer is sugar crystals with stirring at 15 degrees Celsius. 
Solubility is the maximum amount of a substance that will dissolve in a given amount of solvent at a specific temperature. There are two major factors that affect solubility are temperature and pressure. Temperature affects solubility of both solids and gases, but pressure only affects the solubility of gases. Increasing the surface area of solutes also increases the solubility. 
5 0
2 years ago
Read 2 more answers
Which of the following is a valid conversion factor?
VMariaS [17]

Answer:

100 cg/1g

Step-by-step explanation:

    1 cg = 0.01 g     Multiply by 100

100 cg = 1 g

(a) is <em>wrong</em>. The correct conversion factor is 1000 cm³/1 L.

(b) is <em>wrong</em>. The correct conversion factor is 1000 mL/1 L.

(c) is <em>wrong</em>. The correct conversion factor is 1 m/10 dm.

7 0
2 years ago
Read 2 more answers
How many moles of sodium bicarbonate is needed to neutralize 0.8 ml of sulphuric acid?
svet-max [94.6K]

Answer:

n NaHCO3 = 9.6 E-3 mol

Explanation:

balanced reaction:

  • 2 NaHCO3(s) + H2SO4(ac) ↔ Na2SO4(ac) + 2 CO2(g) + 2 H2O(l)
  • assuming a concentration of H2SO4 6M....normally worked in the lab

⇒ n H2SO4 = 8 E-4 L * 6 mol/L = 4.8 E-3 mol H2SO4

according to balanced reaction, we have that for every mol of H2SO4 there are two mol of NaHCO3 ( sodium bicarbonate)

⇒ mol NaHCO3 = 4.8 E-3 mol H2SO4 * ( 2 mol NaHCO3 / mol H2SO4 )

⇒ ,mol NaHCO3 = 9.6 E-3 mol

So 9.6 E-3 mol NaHCO3,  are the minimun moles necessary to neutralize the acid.

6 0
2 years ago
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