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2 years ago

Calculate the mass of MNO2 needed to produce 25.0 g of Cl2

Chemistry

2 answers:

ycow [4]2 years ago

8 0

Answer: The mass of $MnO_2$ required is 30.6 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of chlorine gas = 25.0 g

Molar mass of chlorine gas = 71 g/mol

Putting values in equation 1, we get:

$\text{Moles of chlorine gas}=\frac{25.0g}{71g/mol}=0.352mol$

The chemical equation for the reaction of manganese (IV) oxide and hydrochloric acid follows:

$MnO_2+4HCl\rightarrow MnCl_2+Cl_2+2H_2O$

By Stoichiometry of the reaction:

1 mole of chlorine gas is produced when 1 mole of $MnO_2$ is reacted.

So, 0.352 moles of chlorine gas is produced when $\frac{1}{1}\times 0.352=0.352mol$ of $MnO_2$ is reacted.

Now, calculating the mass of $MnO_2$ by using equation 1, we get:

Molar mass of $MnO_2$ = 87 g/mol

Moles of $MnO_2$ = 0.352 moles

Putting values in equation 1, we get:

$0.352mol=\frac{\text{Mass of }MnO_2}{87g/mol}\\\\\text{Mass of }MnO_2=(0.352mol\times 87g/mol)=30.6g$

Hence, the mass of $MnO_2$ required is 30.6 grams.

Vedmedyk [2.9K]2 years ago

7 0

I will solve this question assuming the reaction equation look like this:
MnO2 + 4 HCl ---> MnCl2 + Cl2 + 2 H2O.

For every one molecule of MnO2 used, there will be one molecule of Cl2 formed. If the molecular mass of MnO2 is 87g/mol and molecular mass of Cl2 is 73.0 g/mol, the mass of MnO2 needed would be:
Cl mass/Cl molecular mass * MnO2 molecular mass=
25g/ (73g/mol) * (87g/mol) * 1/1= 29.8 grams

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2 years ago

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During a lab experiment performed at STP conditions, you prepare HCl by reacting 100. ml of Cl2 gas with an excess of H2 gas.

Brrunno [24]

Answer: 19.4 mL Ba(OH)2

Explanation:

H2(g) + Cl2(g) --> 2HCl(aq) (make sure this equation is balanced first)

At STP, 1 mol gas = 22.4 L gas. Use this conversion factor to convert the 100. mL of Cl2 to moles.

0.100 L Cl2 • (1 mol / 22.4 L) = 0.00446 mol Cl2

Use the mole ratio of 2 mol HCl for every 1 mol Cl2 to find moles of HCl produced.

0.00446 mol Cl2 • (2 mol HCl / 1 mol Cl2) = 0.00892 mol HCl

HCl is a strong acid and Ba(OH)2 is a strong base so both will completely ionize to release H+ and OH- respectively. You need 0.00892 mol OH- to neutralize all of the HCl. Note that one mole of Ba(OH)2 contains 2 moles of OH-.

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2 years ago

A piece of iron (C=0.449 J/g°C) and a piece of gold (C=0.128 J/g°C) have identical masses. If the iron has an initial temperatur

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Answer:

The correct answer is B. Since the two metals have the same mass, but the specific heat capacity of iron is much greater than that of gold, the final temperature of the two metals will be closer to 498 K than to 298 K

Explanation:

Iron is hotter and gold is colder, therefore, according to laws of thermodynamics, iron will lose heat to gold until they are at the same temperature.

The specific heat capacity of iron(0.449) is over three times that of gold(0.128). Since masses are equal, this means that each time iron's temperature drops by one degree, the energy released it releases makes gold's temperature increase by more than 3 degrees. So gold's temperature will be climbing much faster than iron's is falling. Meaning they will meet closer to the initial temperature of iron than that of gold

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