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Snowcat [4.5K]
2 years ago
5

5. A guava with a mass of 0.200 kg has a weight of

Chemistry
2 answers:
Hatshy [7]2 years ago
6 0
It’s b and could I have the Brianliest plzzzz
monitta2 years ago
4 0
The magnitude of gravity is equivalent to about 9.8m/s^2

Weight by definition is mass multiplied by gravity. Do 0.2*9.8 to get 1.96 Newtons
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3. What is the volume of a salt crystal measuring 2.44 x 10-2 m by 1.4 x 10-3 m by 8.4 x 10-3 m?
AlexFokin [52]

Answer:

2.9× 10⁻⁷ m³

Explanation:

Given data:

Measurements of crystal = 2.44 × 10⁻² m by  1.4 × 10⁻³ m by 8.4  × 10⁻³ m

Volume = ?

Solution:

Volume is equal to the length by width by height.

<em>So from given measurement value:</em>

Volume =  2.44 × 10⁻² m by  1.4 × 10⁻³ m by 8.4  × 10⁻³ m

Volume = 2.9× 10⁻⁷ m³

So the volume from given values is 2.9× 10⁻⁷ m³.

8 0
2 years ago
Calculate the first and second velocities of the car with one washer attached to the pulley, using the formulas v1 = 0.25 m / t1
labwork [276]

Answer: .11  .28

Explanation:

I was on this lesson

8 0
2 years ago
Read 2 more answers
the air we breathe is approximately 21% oxygen.atypical breath has a volume of 450 ml.how many grams of O2 are in a breath of ai
nirvana33 [79]
<span>We breathe around an average of 500 ml of air in 1 normal (or relax) breathing. The lungs already have around 3 litres of reserve breathing. Since there is around 21% oxygen in air, we breathe in around 105 ml of Oxygen from the air. That is equal to around 0.14 g of Oxygen.</span>
6 0
2 years ago
What is the change in enthalpy associated with the combustion of 530 g of methane (CH4)?Report your answer in scientific notatio
Veseljchak [2.6K]

Answer:

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

Explanation:

CH_4+2O_2\rightarrow CO_2+2H_2O,\Delta H_{comb}=-890.8 kJ/mol

Mass of methane burnt = 530 g

Moles of methane burnt = \frac{530 g}{16 g/mol}=33.125 mol

Energy released on combustion of 1 mole of methane = -890.8 kJ/mol

Energy released on combustion of 33.125 moles of methane :

-890.8 kJ/mol\times 33.125 mol=-29,507.75 kJ=-2.950775\times 10^4 kJ

-2.950775\times 10^4 kJ\approx -3.0\times 10^4 kJ

-3.0\times 10^4 kJ is the change in enthalpy associated with the combustion of 530 g of methane.

7 0
2 years ago
Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to
valina [46]

5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.

<u>Explanation</u>:

  • Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:

                        Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃

  • From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of  H₂SO₄.
  • Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and                                Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
  • To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is =  5.451 X 10³ kg.

 

5 0
2 years ago
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