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2 years ago

5. A guava with a mass of 0.200 kg has a weight of

Chemistry

2 answers:

Hatshy [7]2 years ago

6 0

It’s b and could I have the Brianliest plzzzz

monitta2 years ago

4 0

The magnitude of gravity is equivalent to about 9.8m/s^2

Weight by definition is mass multiplied by gravity. Do 0.2*9.8 to get 1.96 Newtons

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What is the oxidation number of pt in k2ptcl6?

padilas [110]

Your compound is $K_{2}PtCl_{6}$ .

Remember that the oxidation numbers in a neutral compound must add up to zero. Cl has an oxidation number of -1 because it is a halogen K has an oxidation number of +1 because it is an alkali metal, which exhibits an oxidation state of +1 in compounds.

Since you have 6 atoms of Cl, you have -1(6) = -6 for the Cl. Since you 2 atoms of K, you have +1(2) = +2 for the K. The oxidation number of Pt must make all the oxidation numbers add up to zero:
+2 + (-6) + oxidation number of Pt = 0
-4 + oxidation number of Pt = 0
Oxidation number of Pt = 4

4 0

2 years ago

The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of

AlexFokin [52]

Answer: C. 25.6 kPa

Explanation:

The Gauge pressure is defined as the amount of pressure in a fluid that exceeds the amount of pressure in the atmosphere.

As such, the formula will be,

PG = PT – PA

Where,

PG is Gauge Pressure

PT is Absolute Pressure

PA is Atmospheric Pressure

Inputted in the formula,

PG = 125.4 - 99.8

PG = 25.6 kPa

The gauge pressure inside the container is 25.6kPa which is option C.

4 0

2 years ago

How many atoms are in a molecule of RSq?

Wewaii [24]

2 atoms in a molecule of RSq, TSq contains 3 different types of atoms (Sq, R, and T.)

6 0

2 years ago

What is the number of moles in 15.0 g AsH3?

Grace [21]

Answer:

0.192 mol.

Explanation:

To calculate the no. of moles of a substance (n), we use the relation:

<em>n = mass / molar mass.</em>

mass of AsH₃ = 15.0 g.

molar mass of AsH₃ = 77.95 g/mol.

∴ The number of moles in 15.0 g AsH₃ = mass / molar mass = (15.0 g) / (77.95 g/mol) = 0.192 mol.

7 0

1 year ago

Avogadro’s number was calculated by determining the number of atoms in 12.00 g of carbon-12. 14.00 g of carbon-12. 12.00 g of ox

OLga [1]

Answer:

Avogadro’s number was calculated by determining the number of atoms in 12.00 g of carbon-12.

Explanation:

The number of particles presents in one mole of a substance is known as Avogadro's number.

Avogadro's number is $6.022\times10^2^3$ atoms or molecules or ions or particles present in one mole of a substance. It is denoted by the symbol $L$ or $N_A$ . It is a dimensionless quantity.

Avogadro's number was proposed by Jean Perrin but named in the honor of italian scientist Amedeo Avogadro.

Avogadro's number is the number of atoms present in 12 grams of carbon-12.

8 0

2 years ago

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