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Elza [17]
2 years ago
8

All of the following contribute to the large, negative, free-energy change upon hydrolysis of "high-energy" compounds except: a.

stabilization of products by extra resonance forms b. stabilization of products by ionization c. low activation energy of the forward reaction d. electrostatic repulsion in the reactant
Chemistry
1 answer:
klasskru [66]2 years ago
8 0

Answer:

C) low activation energy of forward reaction

Explanation:

Activation energy for the forward reaction is the quantity of free energy which is needed for a reaction to move from the reactant phase of energy level to the transition state of energy level. The higher the rate of energy level, the slower the chemical reaction.

Activation energy is a barrier that must be overcome for a reaction to take place.

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You wish to extract an organic compound from an aqueous phase into an organic layer (three to six extractions on a marco scale).
AVprozaik [17]

Answer:

Explanation:

It will be better to use solvents that are lighter than water, because their density has an influence on the miscibility . This will give you a better separation during extraction.

7 0
2 years ago
Which industrial facility is most likely to produce toluene and benzene wastes?
lesantik [10]

Well, you didn't give me any options so if this isn't the answer to your pacific question then I apologize.

but most likely a steel smelting facility.

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5 0
1 year ago
Read 2 more answers
The K w for water at 0 ∘ C is 0.12 × 10 − 14 M 2 . Calculate the pH of a neutral aqueous solution at 0 ∘ C . p H = Is a pH = 7.2
labwork [276]

Answer:

pH → 7.46

Explanation:

We begin with the autoionization of water. This equilibrium reaction is:

2H₂O  ⇄   H₃O⁺  +  OH⁻            Kw = 1×10⁻¹⁴         at 25°C

Kw = [H₃O⁺] . [OH⁻]

We do not consider [H₂O] in the expression for the constant.

[H₃O⁺] = [OH⁻] = √1×10⁻¹⁴   →  1×10⁻⁷ M

Kw depends on the temperature

0.12×10⁻¹⁴ = [H₃O⁺] . [OH⁻]  → [H₃O⁺] = [OH⁻]         at 0°C

√0.12×10⁻¹⁴ = [H₃O⁺] → 3.46×10⁻⁸ M

- log [H₃O⁺] = pH

pH = - log 3.46×10⁻⁸ → 7.46

5 0
2 years ago
Summarize the process a scientist goes through to come up with a<br> satisfactory solution.
maria [59]
Guess and check, test, trial and error, completion.
6 0
2 years ago
Time Remaining: 1:27:31 If 50.0 g of H₂ and 100.0 g of O₂ react, how many moles of H₂O can be produced in the reaction below? 2
Novay_Z [31]

Answer:

Explanation:

2 H₂(g) + O₂(g) → 2 H₂O(g

2 moles     1 mole      2 mole

50 g of H₂ = 50 /2 = 25 moles of H₂

100 g of O₂ = 100 / 32 = 3.125 moles of O₂

So oxygen is the limiting reagent .

3.125 moles of O₂ will react with 6.25 moles of H₂ to give 6.25 moles of H₂O .

Hence moles of H₂O produced = 6.25 moles .

6 0
1 year ago
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