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Rasek [7]
2 years ago
5

Summarize the process a scientist goes through to come up with a satisfactory solution.

Chemistry
1 answer:
maria [59]2 years ago
6 0
Guess and check, test, trial and error, completion.
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9. A Toyota Prius hybrid gets 21 kilometers per liter in highway driving. What is
Rom4ik [11]

Answer:

...................................................................................

6 0
2 years ago
Why is it important to ensure that treated water remains safe to drink when it is stored after treatment? what is one way to mak
yarga [219]


It is important to ensure that treated water remains safe to drink because water does not last forever as it can gain bacteria and organisms in it. To make sure storage of water is safe is to simply add chlorine again over a period of time.

-never store in direct sunlight

-containment of the water is clean

-make sure chemicals or anything that can contaminate it doesn't come near it

7 0
2 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
KATRIN_1 [288]

Answer : The initial temperature of the limestone is 1.05\times 10^{2}^oC.

Solution : Given,

Mass of limestone = 62.6 g

Mass of water = 75 g

Final temperature of limestone = 51.9^oC

Final temperature of water = 51.9^oC

Initial temperature of water = 23.1^oC

The specific heat capacity of limestone = 0.921J/g^oC

The specific heat capacity of water = 4.186J/g^oC

The formula used :

q = m × c × ΔT

where,

q = heat required

m = mass of an element

c = heat capacity

ΔT = change in temperature

According to this, the energy as heat lost by the system is equal to the gained by the surroundings.

Now the above formula converted and we get

q_{system}=-q_{surrounding}

m_{system}\times c_{system}\times (T_{final}-T_{initial})_{system}= -[m_{surrounding}\times c_{surrounding}\times (T_{final}-T_{initial})_{surrounding}]

m_{limestone}\times c_{limestone}\times (T_{final}-T_{initial})_{limestone}= -[m_{water}\times c_{water}\times (T_{final}-T_{initial})_{water}]

Now put all the given values in this formula, we get

62.6g\times 0.921J/g^{0}C \times (51.9^{0}C-T_{\text{ initial limestone}})= -[75g\times 4.186J/g^{0}C \times (51.9^{0}C-23.1^oC)]

By rearranging the terms, we get  the value of initial temperature of limestone.

T_{\text{ initial limestone}}=104.926^{0}C=1.05\times 10^{2}^oC

Therefore, the initial temperature of the limestone is 1.05\times 10^{2}^oC.




8 0
2 years ago
Read 2 more answers
In chemistry we did a lab examining iron nails corroding in agar. One of the nails was wrapped in zinc, and the nail did not rus
forsale [732]

Answer:

Zn(OH)₂

<em>Explanation: </em>

Zn is above Fe in the activity series, so it is more readily oxidized:

Zn(s) ⟶ Zn²⁺(aq) + 2e⁻

The zinc ions go into solution.

The electrons travel from the Zn to the surface of the iron nail, where they reduce the water to hydrogen and hydroxide ions.

2H₂O(ℓ) + 2e⁻ ⟶ H₂(g) + 2OH⁻(aq)

Neither the zinc ions nor the hydroxide ions can move far through the gel.

Their concentration builds up around the hail. The ions find each other and form a precipitate.

Zn²⁺(aq) + 2OH⁻(aq) ⟶  Zn(OH)₂(s)

4 0
2 years ago
1. What volume of toluene do you need to add to 1 mL of ethyl acetate to make an equi-molar mixture? The density of ethyl acetat
galben [10]

Answer:

1.06 mL of toluene will be needed.

Explanation:

Equi-molar mixture means equal moles of all the components.

as given the volume of ethyl acetate = 1mL

Density of ethyl acetate = 0.898 g/mL

The relation between density, mass and volume is :

density=\frac{mass}{volume}

mass=volumeXdensity

mass of ethyl acetate present = 1mL X 0.898g/mL = 0.598 grams

the moles are related to mass as:

moles=\frac{mass}{molarmass}

For ethyl acetate molar mass = 4X12+8X1+2X16= 88g/mol

moles of ethyl acetate will be:

moles=\frac{0.898}{88}= 0.01mol

So we need 0.01 moles of toluene also

For 0.01 moles the mass of toluene required = 0.01 X molar mass of toluene

mass required = 0.01 X 92=0.92grams

for 0.92 grams of toluene volume required will be:

volume=\frac{mass}{density}=\frac{0.92}{0.867}= 1.06mL

4 0
2 years ago
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