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diamong [38]
2 years ago
3

A complex electronic device contains three components, A, B, and C. The probabilities of failure for each component in any one y

ear are 0.01, 0.03, and 0.04, respectively. If any one component fails, the device will fail. If the components fail independently of one another, what is the probability that the device will not fail in one year?
Mathematics
1 answer:
kvasek [131]2 years ago
4 0

Answer:

0.9219 or 92.19%

Step-by-step explanation:

The probability that the device will not fail in one year is given by the joint probability that none of the three components will fail within the year. The individual probabilities of not failing are:

P(A) = 1-0.01 = 0.99\\P(B) = 1-0.03 = 0.97\\P(C) = 1-0.04 = 0.96

The joint probability is:

P(A \cap B\cap C) =0.99*0.97*9.96\\P(A \cap B\cap C) =0.9219 = 92.19\%

There is a 0.9219 or 92.19% probability that the device will not fail in one year.

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The answer is figure C

Step-by-step explanation:

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A research organization wanted to estimate the average number of hours a college student sleeps per night during the school year
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Step-by-step explanation:

Given given that

  • Lower confidence interval = 7.1
  • Upper confidence interval = 7.5
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Average value = LCI + UCI /2 = 7.1 + 7.5 / 2

= 7.3hours per night, so we are 95% confident that it's somewhere between 7.1 and 7.5 hours per night which is eventually 7.3hrs per night.

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Rex walks 3 1/7 km in 1 1/4 hours. At the same speed , how long will he go in one hour? Simplify your answer and write it as a p
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She walks 22/7 km in 5/4 hrs, so she walks (22/7)/(5/4) km, or 88/35 (2_18/35) km, in 1 hr.
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2 years ago
In general, the probability that it rains on Saturday is 25%. If it rains on Saturday, the probability that it rains on Sunday i
lora16 [44]

Answer:

40%

Step-by-step explanation:

From the given statements:

The probability that it rains on Saturday is 25%.

P(Sunday)=25%=0.25

Given that it rains on Saturday, the probability that it rains on Sunday is 50%.

P(Sunday|Saturday)=50%=0.5

Given that it does not rain on Saturday, the probability that it rains on Sunday is 25%.

P(Sunday|No Rain on Saturday)=25%=0.25

We are to determine the probability that it rained on Saturday given that it rained on Sunday, P(Saturday|Sunday).

P(No rain on Saturday)=1-P(Saturday)=1-0.25=0.75

Using Bayes Theorem for conditional probability:

P(Saturday|Sunday)=\frac{P(Sunday|Saturday)P(Saturday)}{P(Sunday|Saturday)P(Saturday)+P(Sunday|No Rain on Saturday)P(No Rain on Saturday)}

=\frac{0.5*0.25}{0.5*0.25+0.25*0.75}

=0.4

There is a 40% probability that it rained on Saturday given that it rains on Sunday.

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2 years ago
On the first january 2014 carol invested some money in a bank account the account payes 2.5% compound interest per year on 1st j
Sladkaya [172]

Answer:

$23,360

Step-by-step explanation:

Calculation to determine how much carol originally invested in the account

First step is to divide £23517.60 by 1.025

= (23,517.60)/(1+.025)

= (23,517.60)/1.025

=$22,944

Second step is to add back the $1,000 withdrew

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Now let calculate how much carol originally invested in the account

$23,944=1.025P

Divide both side by 1.025

P=$23,944/1.025

P=$23,360

Therefore the amount that carol originally invested in the account is $23,360

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2 years ago
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