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2 years ago

A student writes the equation for a line that has a slope of -6 and passes through the point (2, –8).

Mathematics

1 answer:

tester [92]2 years ago

3 0

Answer:

y -(-8) = -6(x - 2) or y - (-8) = -6x + 12

Step-by-step explanation:

gradient(m) = -6 point (2,-8)

equation of a line is given as;

y - y1 = m(x - x1)

y - (-8) = -6(x - 2)

y - (-8) = -6x - 12

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Suppose that – in any given time period – a certain stock is equally likely to go up 1 unit or down 1 unit, and that the outcome

Scorpion4ik [409]

Answer:

Step-by-step explanation:

From the given information:

Let X represent the amount of the stock that goes up in the first period; &

Let Y denote the cumulative amount that goes up in the first three periods.

Then,

$X= X_1 + X_2 \\ \\ \\EX= EX_1 +EX_2\\ \\\\Now ; EX = 0 \\ \\ EX = \dfrac{1}{2}\times 1 + \dfrac{1}{2}\times -1 \\ \\ EX = \dfrac{1}{2}-\dfrac{1}{2} \\ \\ EX = 0$

$Cov(x,y) = Var(X_1) +Var(X_2) \\ \\ =\dfrac{1}{2}(1+1) + \dfrac{1}{2}(1+1) \\ \\ = \dfrac{1}{2}(2)+ \dfrac{1}{2}(2) \\ \\ = 1+1 \\ \\ =2$

$Var (X) = Var (X_1+X_2)\\ \\ = 2 \ Var(X_1) \\ \\ = 2 \times (1) \\ \\ = 2$

$Var (Y) = Var (X_1 +X_2+X_3) \\ \\ = 3 \times Var(X_1) = \\ \\ = 3 \times 1\\ \\ = 3$

∴

$Corr(x,y) = \dfrac{2}{\sqrt{6}} \\ \\ = \dfrac{2}{\sqrt{2\times 3}} \\ \\= \sqrt{\dfrac{2}{3}}$

3 0

1 year ago

Catherine jogged 2/9 hour on her first day of training for the track team. What decimal represents the amount of time she spent

Andru [333]

Answer:

0.22 hour, or 13.33 minutes

Step-by-step explanation:

2/9 hour is roughly equivalent to 0.22 hour, or 13.33 minutes.

8 0

2 years ago

The graph of a hyperbola is shown.

Veseljchak [2.6K]

Answer:the length of the transverse axis is 18 units. Option C is the correct answer

Step-by-step explanation:

The transverse axis is the line segment which passes through the center of the hyperbola and its endpoints are the vertices of the hyperbola. Looking at the diagram of the hyperbola given, it has two foci at - 15 and 15 on the x axis. It has two vertices at - 9 and 9 on the x axis. Therefore the length of the transverse axis is -9 to 9. It becomes

9 - - 9 = 18

4 0

2 years ago

Read 2 more answers

"Consider the probability distribution of X, where X is the number of job applications completed by a college senior through the

Citrus2011 [14]

Answer:

Option b

Step-by-step explanation:

Given that the probability distribution of X, where X is the number of job applications completed by a college senior through the school’s career center.

Expected observed Diff

x p(x) p(x)*1000

0 0.002 2

1 0.011 11 14 -3

2 0.115 115 15 100

3 0.123 123 130 -7

4 0.144 144

5 0.189 189

6 0.238 238

7 0.178 178

1 1000

We find that there is a large difference in 2 job application

Hence option b is right.

4 0

2 years ago

Simplify 100y^3/98xy pls answer soon hegarty maths lazy

OleMash [197]

Answer:

50y^4x/49

Step-by-step explanation:

y^3/98

((100* y^3/98 * x) * y

2.1 y^3 * y^1=y^(3+1)=y^4

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2 years ago