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riadik2000 [5.3K]

2 years ago

14

In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figu

re.

2 answers:

alukav5142 [94]2 years ago

8 0

Answer:

Step-by-step explanation:

the answer is e times d times b plus a then you get solve it yourself @@#@#.

myrzilka [38]2 years ago

5 0

https://www.omnicalculator.com/math/perimeter

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Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

nikklg [1K]

Answer:

a. 5 + 2i, 13 + 2i, 29 + 2i

Step-by-step explanation:

We'll use the formula f(z) = 2z + (3 - 2i) for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with z0 = 1 + 2i and we plug that into the base equation:

z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i

z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i

z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i + 3 - 2i = 29 + 2i

z3 = 29 + 2i

8 0

2 years ago

Read 2 more answers

On average, a major earthquake (Richter scale 6.0 or above) occurs three times a decade in a certain California county. Find the

ahrayia [7]

Correct answer should be D

8 0

2 years ago

1- find the first term= ?, 90, 540, 3240

Luda [366]

Answer:

1. 15

2. 8

Step-by-step explanation:

The two sequence are geometric progression GP, because they follow a constant multiple (common ratio)

The nth term of a GP is;

Tn = ar^(n-1)

Where;

a = first term

r = common ratio

For the first sequence;

The common ratio r is

r = T3/T2 = 540/90 = 6

r = 6

T2 = ar^(2-1) = ar

T2 = 90 = ar

Substituting the values of r;

90 = a × 6

a = 90/6

a = 15

First term = 15

2. The sam method applies here.

Common ratio r = T3/T2 = 128/32 = 4

r = 4

T2 = ar^(2-1) = ar

T2 = 32 = ar

Substituting the values of r;

32 = a × 4

a = 32/4

a = 8

First term = 8

4 0

2 years ago

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A

lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

Part A: <u>ΔABC is similar to ΔADC</u>

Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>

Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

$\displaystyle \frac{\overline{DA}}{\overline{DC}} = \frac{\overline{BD}}{\overline{DA}}$

$\overline{DA}^2$ = $\overline{DC} \times \overline{BD}$

Which gives;

$\overline{DA}^2$ = 4 × 9 = 36

$\overline{DA}$ = √(36) = 6

$\overline{DA}$ <u> = 6</u>

Learn more here:

brainly.com/question/2269451

3 0

1 year ago

a tip jar contains 48 coins, all nickels, dimes, and quarters. the total value of the coins in 5.40. if thr value of the dimes i

Butoxors [25]

Answer:

number of nickle coins = 20

number of dime coins = 11

number of quarter coins = 17

Step-by-step explanation:

Worth of coins in one dollar : 1 quarter = 25% , 1 dime = 10%, 1 nickle = 5%

Now, let number of nickle coins be x and number of quarter coins be y

Number of dimes = 55% less than number of nickle

⇒ Number of dimes = 0.55·x

Now, according to question, Total number of coins in the jar = 48

⇒ x + 0.55·x + y = 48

⇒ 1.55·x + y = 48.........(1)

Total value of coins in the jar = 5.40

⇒ 0.05·x + 0.01 × 0.55·x + 0.25·y = 5.40

⇒ 0.0555·x + 0.25·y = 5.40

⇒ 5.55·x + 25·y = 540..........(2)

On solving (1) and (2), We get

x = 19.88 ≈ 20

y = 17.19 ≈ 17

Hence, number of nickle coins = 20

number of dime coins = 11

number of quarter coins = 17

3 0

2 years ago