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AleksAgata [21]
2 years ago
13

There are 3 alternative routes by which you may drive to work: Alabaster Street, Brillantine Street, and Clancy Street. It is th

e beginning of rush hour, and by experience Alabaster street will be closed by a car crash on average in 25 minutes, Brillantine street in 50 minutes, and Clancy Street in 40 minutes. Accident times are completely unpredictable. If you leave for work in one hour (60 minutes), what is the probability that (at the moment you leave) a route to work will still be open?
Mathematics
1 answer:
Solnce55 [7]2 years ago
3 0

Answer:

25%

Step-by-step explanation:

sorry i did it in my head

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Round 3659 to the nearest thousand
Kryger [21]
It is 4,000. :P
The 6 in the hundreds tells you to round up. 4 and under, keep it. 5 and up, raise it by one. :)
5 0
2 years ago
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Which of the following lists of three numbers could form the side lengths of a triangle? <img src="https://tex.z-dn.net/?f=A.%20
yan [13]

Answer:

B. 122, 257, 137

Step-by-step explanation:

The triangle inequality rule states that the sum of any two sides of a triangle must be greater than the third side. If A, B and C are sides of a triangle then A + B > C, A + C > B, B + C > A

Testing for the options:

1) 10, 20, 30

10 + 20 (= 30) is not greater than 30. It cannot form a triangle

2) 122, 257, 137

122 + 137 (259) is greater than 257. It can form a triangle

3) 8.6, 12.2, 2.7

8.6 + 2.7 (11.3) is not greater than 12.2. It cannot form a triangle

4) 1/2, 1/5, 1/6

1/5 + 1/6 (11//30) is not greater than 1/2. It cannot form a triangle

8 0
2 years ago
A six-sided number cube is labeled with the numbers 1-6, one number on each face. Each number is used exactly once. How
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3 0
2 years ago
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The area of the surface of the swimming pool is 210 square feet. what is the lenght d of the deep end (in feet)?
madreJ [45]
The lenth at the deep end is 12 ft becuase u divide 210 and 12 and if it goes into it evenly u got ur answer
3 0
2 years ago
Jason swam 3 and one-half miles, then another 3 1/4th miles in one day. On the same day, Rachel swam 2 2/3rd miles, then another
Fynjy0 [20]
<h2>Hello!</h2><h2>The answer is:</h2>

Rachel swam  \frac{5}{12}   miles or 0.42 miles   more than Jason.

<h2>Why?</h2>

To calculate how many miles did Rachel swim more than Jason, we need to write the following equation:

Difference=RachelMiles-JasonMiles

Where,

Difference, is equal to the number of Miles that Rachel did more than Jason

RachelMiles, is equal to 2 2/3rd miles plus 4.5 miles.

Jason Miles, is equal to 3.5 miles plus 3 1/4th miles.

Also, we need to remember the following:

- How to convert mixed fractions to improper fractions,

a\frac{b}{c}=a+\frac{b}{c}

- How to add or subtract fractions and whole numbers.

a+\frac{b}{c}=\frac{ac+b}{c}

Now, we are given the following information:

Jason's miles:

JasonMiles=3\frac{1}{2}+3\frac{1}{4} =(3+\frac{1}{2})+(3+\frac{1}{4})\\\\JasonMiles=(3+\frac{1}{2})+(3+\frac{1}{4})=(\frac{(2)*(3)+1}{2})+(\frac{(3)*(4)+1}{4})\\\\JasonMiles=(\frac{(2)*(3)+1}{2})+(\frac{(3)*(4)+1}{4})=\frac{7}{2}+\frac{13}{4}\\\\JasonMiles=\frac{(7)*(4)+(2)*(13)}{8}=\frac{28+26}{8}=\frac{54}{8}\\\\JasonMiles=\frac{54}{8}=\frac{27}{4}miles

Rachel's miles:

RachelMiles=2\frac{2}{3}+4\frac{1}{2}=(2+\frac{2}{3})+(4+\frac{1}{2})\\\\RachelMiles=(2+\frac{2}{3})+(4+\frac{1}{2})=(\frac{(2)*(3)+2}{3})+(\frac{(4)*(2)+1}{2})\\ \\RachelMiles=(\frac{(2)*(3)+2}{3})+(\frac{(4)*(2)+1}{2})=\frac{6+2}{3} +\frac{8+1}{2}\\\\RachelMiles=\frac{6+2}{3} +\frac{8+1}{2}=\frac{8}{3}+\frac{9}{2}\\\\RachelMiles=\frac{8}{3}+\frac{9}{2}=\frac{(8)*(2)+(3)*(9)}{(3)*(2)}\\\\RachelMiles=\frac{(8)*(2)+(3)*(9)}{(3)*(2)}=\frac{16+27}{6}=\frac{43}{6}miles

Now, substituting the miles swam by Rachel and Jason into the equation, we have:

Difference=\frac{43}{6}-\frac{27}{4}=\frac{(43)*(4)-(6)*(27)}{24}\\\\Difference=\frac{(43)*(4)-(6)*(27)}{24}=\frac{172-162}{24}\\\\Difference=\frac{172-162}{24}=\frac{10}{24}=\frac{5}{12}miles=0.42miles

Hence, we found that Rachel swam 0.42 miles more than Jason.

Have a nice day!

7 0
2 years ago
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