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Lostsunrise [7]
2 years ago
10

The probability of it snowing in Eastern Canada tomorrow is 0.40.40, point, 4. The probability of it snowing in Western Canada t

omorrow is \dfrac25 5 2 ​ start fraction, 2, divided by, 5, end fraction. Which of these events is more likely?
Mathematics
2 answers:
____ [38]2 years ago
8 0

Answer:

<em>They are equally likely to occur</em>

Step-by-step explanation:

<u>Probabilities</u>

The probabilities can be expressed as fractions, decimals or percentages. A probability of 0 indicates an impossible event. A probability of 1 means a sure event. An event is said to be more likely to happen than others if its probability is greater.

We know the probability of it snowing in Eastern Canada tomorrow is 0.40, and we are also aware that the probability of it snowing in Western Canada tomorrow is 2/5. Dividing 2 by 5 we get 0.4. Since both events have the same probability, they are equally likely to occur

Assoli18 [71]2 years ago
7 0

Answer:

Neither. Both events are equally likely

Step-by-step explanation:

You might be interested in
A skating rink charges $0.75 to rent skates and $1.25 per hour to skate. How many hours did Penny skate if she was charged $4.50
ArbitrLikvidat [17]
She was skating for 3 hours.
4 0
2 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
2 years ago
At a financial services company, the mean percent allocation for bonds in a retirement portfolio is 26.9 percent with a populati
guajiro [1.7K]

Answer: it is a right tailed probability

Step-by-step explanation:

Population proportion = 26.9/100 = 0.269

We are dealing with the fact that the probability that the mean bond percent for the sample will be at least 28. This means that the sample proportion is 0.28 or above. This means that it is greater than the population proportion of 0.269

The hypothesis would be

For null hypothesis

p = 0.269

For alternative hypothesis,

p > 0.269

The inequality sign means that it is right tailed.

3 0
2 years ago
Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos
dmitriy555 [2]

Answer: The answer is 30%.


Step-by-step explanation:  Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

p\\\\=\dfrac{3\times 0.45+1\times 0.45+2\times 0.55+2\times 0.45+1\times 0.55+3\times 0.55}{20}\\\\=\dfrac{6}{20}\\\\=0.3\\\\=30\%.

Thus, the probability is 30.

4 0
2 years ago
A treasure map says that a treasure is buried so that it partitions the distance between a rock and a tree in a 5:9 ratio. Marin
djyliett [7]

Answer:

A)  (7.6, 8.8)

which are the coordinates of the treasure.

Missing Problem Statement:

Given Options:

A) (11.4, 14.2)

B) (7.6, 8.8)

C) (5.7, 7.5)

D) (10.2, 12.6)

I have added the picture showing the traced map onto a coordinate plane to find exact location of treasure.

The coordinates of Tree are (16,21)

Coordinates of rock are (3,2)

Step-by-step explanation:

Let,

Coordinates of treasure be (a,b)

d_{1}= distance from tree to treasure

d_{2}=distance from rock to treasure

d_{1}=\sqrt{(16-x)^2 + (21-y)^2}

d_{2}=\sqrt{x\2 + (y-2)^2}

Given ratio between rock and tree, \frac{d_{2}}{ d_{1}}=\frac{5}{9}= 0.55_______(Equation.1)

which will be used to locate the treasure.

Now we just need to cross check by putting the coordinates given in the options one by one to find out value of d_{1},d_{2} and checking if it satisfies the Equation 1.

Check (A) (11.4, 14.2)

d_{2}= 14.8, d_{1}= 8.2,

\frac{d_{2}}{ d_{1}}= 1.8

Check (C) (5.7, 7.5)

d_{2}= 6.13, d_{1}= 16.98,

\frac{d_{2}}{ d_{1}}= 0.36

Check (D) (10.2, 12.6)

d_{2}= 12.8, d_{1}= 10.2,

\frac{d_{2}}{ d_{1}}= 1.25

Check (B) (7.6, 8.8)

d_{2}= 8.2, d_{1}= 14.8,

\frac{d_{2}}{ d_{1}}= 0.55

Which satisfies Equation 1, such that ratio between rock and tree is 5:9 or  \frac{d_{2}}{ d_{1}}=\frac{5}{9}= 0.55

So, the coordinates of the treasure are (B) (7.6, 8.8)

7 0
2 years ago
Read 2 more answers
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