Horizontal lines e and f are cut by vertical lines a and b. At the intersection of lines a and e, the uppercase right angle is (
x + 1) degrees. At the intersection of lines a and f, the bottom right angle is (x minus 3) degrees. At the intersection of lines b and e, the bottom left angle is y degrees. If a ∥ b and e ∥ f, what is the value of y? 87 88 91 92
2 answers:
Answer:
Step-by-step explanation:
Based on the description given in the exercise, you can draw the horizontal lines "e" and "f" cut by the vertical lines "a" and "b".
By definition, when a horizontal line and a vertical line intersect each other, the angle formed by this intersection measures 90 degrees.
A "Right angle" is defined as an angle that measures 90 degrees.
Therefore, if a vertical line intersects a horizontal line, you can say that they are perpendicular.
You can observe in the image attached that the vertical lines "a" and "b" cut the horizontal lines "e" and "f". Therefore, since and
, all the angles formed by this intersections measure 90 degrees.
Therefore, you can conclude that:
You might be interested in
Answer:
There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
The needed function is
Step-by-step explanation:
Let us assume the piece of paper James decides to fold is a SQUARE.
Now, let us assume:
n : the number of times the paper is folded.
y : The number of parts obtained after folds.
Now, if the paper if folded ONCE ⇒ n = 1
Also, when the pap er is folded once, the parts obtained are TWO equal parts.
⇒ for n = 1 , y = 2 ..... (1)
Similarly, if the paper if folded TWICE ⇒ n = 2
Also, when the paper is folded twice, the parts obtained are FOUR equal parts.
⇒ for n = 2 , y = 4 ..... (2)
⇒
Continuing the same way, if the paper is folded SEVEN times ⇒ n = 7
So,
⇒ There are total 128 equal parts.
Lastly, if the paper is folded ELEVEN times ⇒ n = 11
So,
⇒ There are total 2048 equal parts.
Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.
And the needed function is