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2 years ago

If point D is placed on AC, how will the measure of DAB relate to the measure of CAB?

Mathematics

1 answer:

xeze [42]2 years ago

6 0

Answer:angle DAB will be equal to angle CAB

Step-by-step explanation:

AC is a straight line and forms one of the sides of triangle ABC. If point D is placed on line AC, angle DAB would remain equal to angle CAB since they are on the same line the angle formed with line AB remains the same.

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Use the X method to find the solutions of<br><br> 6x2 + 2x – 20 = 0

SVEN [57.7K]

The X method?
2x=8
X=4

5 0

1 year ago

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A homemade lip balm consists of coconut oil and beeswax. Coconut oil costs $0.50 per ounce and beeswax costs $2.00 per ounce. If

Alika [10]

Let

a--------> the total cost in dollars of $6$ ounces of coconut oil

b--------> the total cost in dollars of $5$ ounces of beeswax

we know that

$a=0.50 \frac{\$}{ounce}*6=\$3$

$b=2.00 \frac{\$}{ounce}*5=\$10$

therefore

<u>the answer is</u>

the total cost in dollars of $6$ ounces of coconut oil is $a=\$3$

the total cost in dollars of $5$ ounces ofbeeswax is $b=\$10$

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2 years ago

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At the beginning of the business day, a bank's vault held $575,900. By the end of the day, $(3.5 103) had been added to the vaul

Likurg_2 [28]

3.5*10^3=3,500

3,500+ 575,900=579,400

5 0

1 year ago

An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equ

kompoz [17]

Answer:

0.62% probability that a random sample of 16 bulbs will have an average life of less than 775 hours.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution.

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 800, \sigma = 40, n = 16, s = \frac{40}{\sqrt{16}} = 10$