Answer:
I think the answer is going to be paragraph
Answer:
<em>a. fetch</em>
Explanation:
<em>The device collects a program command from its memory during the run cycle of the fetch.
</em>
It then defines and performs the activities needed for that command. The CPU continuously repeats the cycle of fetching, decoding, and executing a command while the computer is switched on.
computer hardware engineer and database architecture
Answer:
For storing the data into a CD, we need to burn it. And the surface of the CD is comprised of the polycarbonate layer that is molded as the spiral tracks over the surface of the CD. And the Data is being stored as a sequence of minute grooves that are called the pits which are encoded on the spiral tracks. And the region in between the pits is known as lands.
The DVD or the digital video dos is based on the optical data storage which is almost the same as the CD. The analog data is transformed into the digital data, and this is encoded on the disc starting from the inside edge, and towards out. This digital information is being encoded into the surface as pits, and the surface acts as the recording layer. A DVD can hold data up to 4.77 to 8 GB.
Since DVD size is bigger than CD, A DVD drive can read CD, but the CD drive cannot read the DVD,
And unlike the above two, which make use of the red laser for reading and writing, the blu ray makes use of the blue laser. Also, it has the smaller pits, tiny beam as well as small track that together make it possible to store around 25 GB of data in one single blue ray disc. And this is five times more than the size of a DVD.
The Blu ray Discs are good for playing the CD as well as DVD. However, the opposite is not possible due to the size.
Explanation:
Please check the answer section.
Answer and Explanation:
Given that total number of records in a file = 100000
Each record consists of= 240 bytes
Given that B= 2400 bytes.
Then total blocks in file = 100000 records * 240 / 2400
= 10000 blocks.
Time that will take for exhaustive read
= s + r + b.btt
= 16 + 8.3 + (10000) * 0.8
= 8024.3 msec
Now as per given X be the number of records that are searched randomly and it takes more than exhaustive read time.
Hence, X (s + r + btt) > 8024.3
X (16+8.3+0.8) > 8024.3
X > 8024.3/25.1
So that, X > 319.69
Hence, atleast 320 random reads should be made to search the file
