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2 years ago

What is the value of h in the figure below? In this diagram BAD~CBD

Mathematics

2 answers:

liberstina [14]2 years ago

8 0

Answer:

The correct option is E. 8

The value of h is 8 unit.

Step-by-step explanation:

Given:

Δ BAD ~ Δ CBD

AC = 20

DC = 4

∴ $AD = AC - DC=20-4=16$

To Find:

h = ?

Solution:

Δ BAD ~ Δ CBD ................Given

If two triangles are similar then their sides are in proportion.

$\frac{BD}{CD} =\frac{AD}{BD} =\frac{BA}{CB}\ \textrm{corresponding sides of similar triangles are in proportion}\\$

On substituting the given values we get

$\dfrac{BD}{CD} =\dfrac{AD}{BD}$

$\dfrac{h}{4} =\dfrac{16}{h}\\\therefore h^{2}=64\\\therefore h=8\ unit$

The value of h is 8 unit.

Ganezh [65]2 years ago

7 0

Answer:

Step-by-step explanation:

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this squared based pyramid is cut horizontally at a height of 15cm to leave this frustum base area=10cm

scoundrel [369]

Answer:

583.33 cm³

Step-by-step explanation:

From the image attached, the total height (H) of the pyramid is 30 cm, the height of the frustrum (h) = 15 cm, the Frustrum base = lower base = B = 10 cm . To find the length of the upper base (b), we use:

$\frac{b}{H-h}=\frac{B}{H}\\ b=(H-h)\frac{B}{H}\\b=(30-15)\frac{10}{30}=5\\b=5\ cm$

The volume of the frustrum is given by:

$V=\frac{1}{3}h(B_1+B_2+\sqrt{B_1B_2} )\\ Where\ B_1\ is \ the\ area \ of\ the\ upper\ base= 5cm*5cm=25cm^2\\B_1\ is \ the\ area \ of\ the\ lower\ base= 10cm*10cm=100cm^2\\V=\frac{1}{3}(10)(25+100+\sqrt{25*100} )=583.33\\V=583.33\ cm^3$

6 0

2 years ago

To test the impact performance of a 10 cm thick gymnastics mat, a 20 kg cylindrical

denis23 [38]

Answer:

A)196J

B)-208J

C)3467J

Step-by-step explanation:

We are given that a 20 kg cylindrical mass is dropped onto the mat from a height of 1 m above the mat. During the impact, the cylinder’s vertical velocity reaches zero at the instant the mat has compressed to only 4 cm thick.

So, The Mat gets compressed by : 10cm - 4 cm = 6 cm=0.06 m

Using Conservations of energy

Potential energy at the top = Kinetic energy at the point before touching the surface

Kinetic energy = mgh= $20 \times 9.8 \times 1 = 196 J$