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mr_godi [17]
2 years ago
14

Planning for acquisition support activities and requirements that deal with fielding/deployment should begin as early as the: [I

dentify life cycle product support activities and requirements that deal with fielding/deployment (e.g., planning, coordination, organizing deployment teams, materiel release).]
A. Materiel Solution Analysis Phase
B. Engineering and Manufacturing Development Phase
C. Operations and Support Phase
D. Production and Deployment Phase
Business
1 answer:
Nataly [62]2 years ago
8 0

Option A, Materiel Solution Analysis Phase

Explanation:

The equipment answer Analysis  part assesses potential solutions for a required capability in associate Initial Capabilities Document (ICD) and to satisfy the phase-specific Entrance Criteria for ensuing program milestone selected by the Milestone call Authority.

The MSA phase is critical to program fulfilment and attaining materiel readiness because it’s the first possibility to persuade systems sup-portability and affordability by using balancing technology opportunities with operational and sustainment requirements. During this phase, various options are analysed to select the materiel solution and broaden the Technology Development Strategy (TDS) to fill any era gaps.

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Space travel is expensive! For their trip to the Moon, the Apollo astronauts' living quarters were only 213 cubic feet (that's s
RSB [31]

Answer:

5341288

Explanation:

Data provided in the question:

Volume of the living quarters = 213 cubic feet

Now,

The dimensions of the US dollar bills are

width = 2.61 inches

Length = 6.14 inches

Thickness = 0.0043 inches

Thus,

Volume of a single dollar bill = 2.61 × 6.14 × 0.0043

= 0.06890922 cubic inches

Also,

Volume of quarter in cubic inches = 213 × 12³  

[ ∵ 1 ft = 12 inches  ; 1 ft³ = 12³ cubic inches]

Thus,

Volume of quarter in cubic inches = 368064 cubic inches.

Thus,

Number of dollar bills that can fit in there

= [ Volume of quarter in cubic inches ] ÷ Volume of a single dollar bill

= 368064 ÷ 0.06890922

= 5341288.15 ≈ 5341288

8 0
2 years ago
A partial listing of costs incurred at Archut Corporation during September appears below:Direct materials $ 113,000Utilities, fa
Sloan [31]
Total period cost for September is 292,000
6 0
2 years ago
An appliance dealer must decide how many (if any) new microwave ovens to order for next month. The ovens cost $220 and sell for
Vlada [557]

Answer:

Explanation:

Order 0: we have unsold items for which the return is -25

return is -25*(.4*1+.2*2+.1*3) = -25*1.1 = $-27.50

Order 1: we have to sell at a discount if no orders, otherwise sell 1, and unsold items if demand 2 or 3

return is .3*(1/2*300-220) + (1-.3)*(300-220) + -.25*(.2*1+.1*2) = .3*-70+.7*80+-25*(.4) =

-21 + 56 - 10 = $25

Order 2: we have to sell at a discount if 0 or 1 orders, sell 1 or 2, and unsold items if demand 3

return is (.3*2+.4*1)*(1/2*300-220)+(.4*1+(.2+.1)*2)*(300-220)+-25*.1 =1*-70+1*80-25*.1 =

-70 + 80 - 2.5 = $7.50

Order 3:

return is (.3*3+.4*2+.2*1)*(1/2*300-220)+(.4*1+.2*2+.1*3)*(300-220) = 1.9*-70 + 1.1*80 =

-133 + 88 = -$45

Order 1, with a return of $25, as this is the highest return.

b) If we had a perfect information, we would never pay a penalty for underordering or suffer a discounted return from over-ordering

(.4*1+.2*2+.1*3)*(300-220) = 1.1*80 = $88

Then, the value of perfect information is $88 - $25 = $63

c) P(D=0|F) = P(F|D=0)*P(D=0)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.1*.3/(.1*.3+.2*.4+.3*.2+.9*.1)=.03/.26 = 3/26

P(D=1|F) = P(F|D=1)*P(D=1)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.2.4/(.1*.3+.2*.4+.3*.2+.9*.1)=.08/.26 = 4/13

P(D=2|F) = P(F|D=2)*P(D=2)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.3*.2/(.1*.3+.2*.4+.3*.2+.9*.1)=.06/.26 = 3/13

P(D=3|F) = P(F|D=3)*P(D=3)/(P(F|D=0)*P(D=0)+P(F|D=1)*P(D=1)+P(F|D=2)*P(D=2)+P(F|D=3)*P(D=3))=

.9*.1/(.1*.3+.2*.4+.3*.2+.9*.1)=.09/.26 = 9/26

P(D=0|U) = P(U|D=0)*P(0)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.8*.3/(.8*.3+.3*.4+.1*.2+.1*.1)=.24/.39 = 8/13

P(D=1|U) = P(U|D=1)*P(1)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.3*.4/(.8*.3+.3*.4+.1*.2+.1*.1)=.12/.39 = 4/13

P(D=2|U) = P(U|D=`)*P(`)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.2/(.8*.3+.3*.4+.1*.2+.1*.1)=.02/.39 = 2/39

P(D=3|U) = P(U|D=3)*P(3)/(P(U|D=0)*P(D=0)+P(U|D=1)*P(D=1)+P(U|D=2)*P(D=2)+P(U|D=3)*P(D=3))=

.1*.1/(.8*.3+.3*.4+.1*.2+.1*.1)=.01/.39 = 1/39

P(N|D=0 = 1-.1-.8 = .1

P(N|D=1) = 1 - .2 - .3 = .5

P(N|D=2) = 1 - .3 - .1 = .6

P(N|D=3) = 1 - .9 - .1 = 0

P(D=0|N) = P(N|D=0)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))=.1*.3/(.1*.3+.5*.4+.6*.2+.0*.1)= .03/.35 = 3/35

P(D=1|N) = P(N|D=1)*P(D=0)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .5*.4/(.1*.3+.5*.4+.6*.2+.0*.1)= .20/.35 = 4/7

P(D=2|N) = P(N|D=2)*P(D=2)/(P(N|D=0)*P(D=0)+P(N|D=1)*P(D=1)+P(N|D=2)*P(D=2)+P(N|D=3)*P(D=3))= .6*.2/(.1*.3+.5*.4+.6*.2+.0*.1)= .12/.35 = 12/35

P(D=3|N) = 0

If the result of the survey is an F, we have

P(D=0|F) = 3/26

P(D=1|F) = 4/13

P(D=2|F) = 3/13

P(D=3|F) = 9/26

If the order is 0, the return is -25*(1*4/13+2*3/13+3*9/26) = -25*47/26 = -1175/26 = -$45.19

If the order is 1, the return is 3/26*-70+(1-3/26)*80+-25*(1*3/13+2*9/26) = 515/13 = $39.62

If the order is 2, the return is (3/26*2+4/13)*-70+(1*4/13+2*(3/13+9/26))*80 + -25*9/26 =

1835/26 = $70.58

If the order is 3, the return is (3/26*3+4/13*2+3/13)*-70+(1*4/13+2*3/13+3*9/26)*80 =

795/13 = $61.15

We should order 2.

P(D=0|U) = 8/13

P(D=1|U) = 4/13

P(D=2|U) = 2/39

P(D=3|U) = 1/39

If we order 0, the return is (4/13*1+2/39*2+1/39*3)*-25 = -475/39 = -$12.18

If the order is 1, the return is 8/13*-70+(1-8/13)*80+-25*(1*2/39+2*1/39) =-580/39= -14.87

If the order is 2, the return is (8/13*2+4/13)*-70+(1*4/13+2*(2/39+1/39))*80 + -25*1/39 =

-2785/39= -$71.41

If the order is 3, the return is (8/13*3+4/13*2+2/39*1)*-70+(1*4/13+2*2/39+3*1/39)*80 =

-1780/13 = -$136.92

Order 0

P(D=0|N) = 3/35

P(D=1|N) = 4/7

P(D=2|N) = 12/35

P(D=3|N) = 0

If we order 0, the return is (4/7*1+12/35*2)*-25 = -220/7 = -$31.43

If the order is 1, the return is 3/35*-70+(1-3/35)*80+-25*(1*12/35) = 410/7 = $58.57

If the order is 2, the return is (3/35*2+4/7)*-70+(1*4/7+2*12/35)*80 = 340/7 = $48.57

We don't order 3, as the probability of 3 is 0

we order 1

We order 2 if there is an F, 0 if there is an N, and 1 if there is a U.

d) P(F) = .26

P(N) = .39

P(U) = .35

Then, the expected return is .26*1835/26 +-475/39*.39 + 410/7*.35 = $34.10

Since we make $25 if we just take 1, we should pay up to $34.10-$25 = $9.10 for the survey.

5 0
2 years ago
Harrison Enterprises currently produces 8,000 units of part B13. Current unit costs for part B13 are as follows: Direct material
Yakvenalex [24]

Answer:

It is cheaper to make the part in house.

Explanation:

Giving the following information:

Harrison Enterprises currently produces 8,000 units of part B13.

Current unit costs for part B13 are as follows:

Direct materials $12

Direct labor 9

Factory rent 7

Administrative costs 10

General factory overhead (allocated) 7

Total $45

If Harrison decides to buy part B13, 50% of the administrative costs would be avoided.

To calculate whether it is better to make the par in-house or buy, we need to determine which costs are unavoidable.

Unavoidable costs:

Factory rent= 7

Administrative costs= 5

General factory overhead= 7

Total= 17

Now, we can calculate the unitary cost of making the product in-house:

Unitary cost= direct material + direct labor + avoidable administrative costs

Unitary cost= 7 + 5 + 5= $17

It is cheaper to make the part in house.

3 0
2 years ago
Nuthatch Corporation began its operations on September 1 of the current year. Budgeted sales for the first three months of busin
EleoNora [17]

Answer:

Option (b) is correct.

Explanation:

Given that,

Budgeted sales in September = $260,000

Budgeted sales in October = $375,000

Budgeted sales in November = $400,000

Percent of merchandise sells for cash = 30%

Percent of merchandise sells on account = 70%

Out of the credit sales,

80% are expected to be collected in the month of the sale.

20% in the month following the sale.

Therefore, the cash collections in September from accounts receivable will include only 80% of the credit sales in September as Nuthatch corporations starts its operation on September 1, hence there will be no sales in August.

Cash Collections From Accounts Receivables;

= 80% of the credit sales in September

= 0.8 × (70% × $260,000)

= 0.8 × $182,000

= $145,600

5 0
2 years ago
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