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mylen [45]
2 years ago
10

Which expression is equivalent to StartFraction (5 a b) cubed Over 30 a Superscript negative 6 Baseline b Superscript negative 7

Baseline EndFraction? Assume a not-equals 0, b not-equals 0.
Mathematics
2 answers:
Misha Larkins [42]2 years ago
8 0

Answer:

Answer: \frac{25}{6} a^{9} b^{10}

Step-by-step explanation:

100% on ed

lorasvet [3.4K]2 years ago
3 0

Answer: \frac{25}{6} a^{9} b^{10}

Step-by-step explanation:

Assuming the described expression is:

\frac{(5ab)^{3}}{30 a^{-6} b^{-7}}

And knowing the condition a \neq 0 and b \neq 0

We cansimplify it following the rules related to the exponents with the same base:

\frac{25}{6} a^{3} b^{3} a^{6} b^{7}

Finally:

\frac{25}{6} a^{9} b^{10}

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Unnithan, Houser, and Fernhall (2006) were interested in whether playing the game Dance Dance Revolution (DDR) met the American
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3 0
2 years ago
I've been stuck on this for so long and I have an exam soon, anybody who can help me :'( ?
san4es73 [151]
(i)  speed = distance / time
so time =  distance / speed
here we have

time t = 1080/x  hours

(ii) return flight  time  = 1080 / (x + 30)  hours

(a)  1080/x - 1080/(x + 30) = 1/2

Multiplying  through by the LCD 2x(x + 30) we get:-

1080*2(x + 30) - 2x*1080 = x(x+30)
2160x + 64800 - 2160x = x^2 + 30x
x^2 + 30x - 64800  = 0

(b)  factoring;  -64800 = 270 * -240  ans 270-240 = 30 so we have

(x + 270)(x - 240) = 0   so x = 240  ( we ignore the negative -270)

So the speed for outward journey is 240 km/hr

(c) time ffor outward flight = 1080 / 240 =  4 1/2  hours

(d) average speed for whole flight = distance / time
   Time for outward journey = 4.5 hours and time for  return journey = d / v
= 1080 / (240+30) =  4 hours
 Therefore the average speed for whole journey =  2160 / 8.5 = 254.1 km/hr
8 0
2 years ago
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