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2 years ago

Of the 13 Journeymen on a jobsite, there are 5 females. What is the ratio of males to females on this job?

Mathematics

2 answers:

AURORKA [14]2 years ago

7 0

Answer:

8:5

Step-by-step explanation:

Ksivusya [100]2 years ago

5 0

Answer: 8 to 5

Step-by-step explanation:

5 females

13-5 males = 8 males

8 to 5

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You have just received an inheritance of $28,000 and would like to invest it into an account. The bank offers two investment pla

grigory [225]

First we need to calculate annual withdrawal of each investment
The formula of the present value of an annuity ordinary is
Pv=pmt [(1-(1+r)^(-n))÷(r)]
Pv present value 28000
PMT annual withdrawal. ?
R interest rate
N time in years
Solve the formula for PMT
PMT=pv÷[(1-(1+r)^(-n))÷(r)]

Now solve for the first investment
PMT=28,000÷((1−(1+0.058)^(−4))
÷(0.058))=8,043.59
The return of this investment is
8,043.59×4years=32,174.36

Solve for the second investment
PMT=28,000÷((1−(1+0.07083)^(
−3))÷(0.07083))=10,685.63
The return of this investment is
10,685.63×3years=32,056.89

So from the return of the first investment and the second investment as you can see the first offer is the yield the highest return with the amount of 32,174.36

Answer d

Hope it helps!

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2 years ago

The height of a baseball hit from a bat is modeled by a quadratic function of time, h(t). What does the second coordinate of the

larisa [96]

The maximum height of the baseball. Hope this helped :)

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2 years ago

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There are exactly π radians in a semicircle. There are exactly π radians in a full circle. There are approximately radians in a

Allisa [31]

pi radians in a semicircle (half circle)

2pi radians in a full circle.

2pi = 2*3.14 = 6.28 approximately, so there are approximately 6.28 radians in a half circle.

2pi radians is equivalent to 360 degrees.

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Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

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2 years ago

Write 11,760,825 in word form and expanded form

tankabanditka [31]

11,000,000 + 700,000 + 60,000 + 800 + 20 + 5 (expanded form)

eleven million seven hundred sixty thousand eight hundred twenty-five (word form)

5 0

2 years ago