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andrew11 [14]
2 years ago
5

There are 10 less trumpet players than saxophone players. The number of saxophone play 3 times the number of trumpet players. Ho

w many trumpet players are there?​
Mathematics
1 answer:
wel2 years ago
5 0

Answer:

there are 20 trumpet players

Step-by-step explanation:

trumpet players=3x-10

saxophone players= 3x

3x + 10 = 3x

3x - 3x=10

therefore x = 10 players

trumpet players = 3x -10

= 3(10)-10

=30-10

= 20 players

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Margarita [4]

For this case, the first thing we must do is define variables.

We have then:

t: number of hours

F (t): total charge

We write the function that models the problem:

F (t) = 6t + b

Where,

b: represents an initial fee.

We must find the value of b.

For this, we use the following data:

Her total fee for a 4-hour job, for instance, is $ 32.

We have then:

32 = 6 (4) + b

From here, we clear the value of b:

32 = 24 + b

32-24 = b

b = 8

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F (t) = 6t + 8

Answer:

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2 years ago
If a cheeseburger weighs a half pound on Earth,<br> what will it weigh on Jupiter?
Katena32 [7]

Answer:

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Step-by-step explanation:

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2 years ago
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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
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Step-by-step explanation:

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xeze [42]

Answer:

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Step 1. Use LCM of the fraction, (2m+3)(2m-3), to simplify the fraction:

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Step 2. Equate the resulting fraction to zero and solve for m:

\frac{-12m}{(2m+3)(2m-3)} =0

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0=0

Since the only solution of the equation holds, the equation bellow doesn't have any extraneous solution

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2 years ago
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