Answer:
The program in Python is as follows:
n = int(input("Enter an integer: "))
if n < 0:
n = 0
print("Sequence:",end=" ")
for i in range(n,-1,-1):
if i%2 == 0:
print(i,end = " ")
Explanation:
This gets input for n
n = int(input("Enter an integer: "))
This sets n to 0 if n is negative
<em>if n < 0:</em>
<em> n = 0</em>
This prints the string "Sequence"
print("Sequence:",end=" ")
This iterates from n to 0
for i in range(n,-1,-1):
This check if current iteration value is even
if i%2 == 0:
If yes, the number is printed
print(i,end = " ")
Answer:
See explaination
Explanation:
StackExample.java
public class StackExample<T> {
private final static int DEFAULT_CAPACITY = 100;
private int top;
private T[] stack = (T[])(new Object[DEFAULT_CAPACITY]);
/**
* Returns a reference to the element at the top of this stack.
* The element is not removed from the stack.
* atreturn element on top of stack
* atthrows EmptyCollectionException if stack is empty
*/
public T peek() throws EmptyCollectionException
{
if (isEmpty())
throw new EmptyCollectionException("stack");
return stack[top-1];
}
/**
* Returns true if this stack is empty and false otherwise.
* atreturn true if this stack is empty
*/
public boolean isEmpty()
{
return top < 0;
}
}
//please replace "at" with the at symbol
Note:
peek() method will always pick the first element from stack. While calling peek() method when stack is empty then it will throw stack underflow error. Since peek() method will always look for first element ffrom stack there is no chance for overflow of stack. So overflow error checking is not required. In above program we handled underflow error in peek() method by checking whether stack is an empty or not.
Answer:
- #include <stdio.h>
- int main()
- {
- const double piVal = 3.14159;
- double sphereVolume = 0.0;
- double sphereRadius = 0.0;
-
- sphereRadius = 1.0;
- sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
-
-
- printf("Sphere volume: %lf\n", sphereVolume);
- return 0;
- }
Explanation:
Firstly we can identify the formula to calculate volume of sphere which is
Volume = 4/3 
With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.
At last, display the sphere volume using printf method (Line 13).
Answer:
I don't know if this is right output is {1,3}
Explanation:
Answer:
see explaination
Explanation:
Function Real calcDiscountPrice(Real price, Real percentage) // Calculate the discount.
Declare Real discount= (price * percentage) / 100.0 // Subtract the discount from the price.
//dividing by 100.0 because of % concept
Declare Real discountPrice = price - discount // Return the discount price.
Return discount End Function
