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EleoNora [17]
2 years ago
10

Assume that month is an int variable whose value is 1 or 2 or 3 or 5 ... or 11 or 12. Write an expression whose value is "jan" o

r "feb or "mar" or "apr" or "may" or "jun" or "jul" or "aug" or "sep" or "oct" or "nov" or "dec" based on the value of month. (So, if the value of month were 4 then the value of the expression would be "apr".).Again, conditional operator so I need to : and ? .(month==1)?"jan":(month==2)?"feb": (month==3)?"mar": (month==4)?"apr": (month==5)?"may":(month==6)?"jun": (month==7)?"jul":(month==8)?"aug":(month==9)?"sep": (month==10)?"oct": (month==11)?"nov": (month==12)?"dec": isn't quite right for the compiler I am currently using.
Computers and Technology
1 answer:
Tamiku [17]2 years ago
7 0

Answer:

The code is given below

Explanation:

The correct syntax would be to place appropriate parenthesis.

(month==1?"jan":(month==2?"feb":(month==3?"mar":(month==4?"apr":(month==5?"may":(month==6?"jun":(month==7?"jul":(month==8?"aug":(month==9?"sep":(month==10?"oct":(month==11?"nov":"dec")))))))))));

Similarly, you can also use the following code:

String[] months = { "jan", "feb", "mar", "apr", "may", "jun", "jul", "aug", "sep", "oct", "nov", "dec" };

int month = 1;

String monthDescription = months[month - 1];

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Sean is using FUNCTION POINT (d) method for forecasting the time and cost of developing a customized software program by looking at the number of inputs, outputs, inquiries, files, and interfaces.

Explanation:

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6 0
2 years ago
A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-lif
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Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

 // variable

float n;  

cout<<"Enter the initial value:";

//Read the input from the user  

cin>>n;

//Declare variables for storing values at 6, 12 and 18 hours

float hours_6, hours_12, hours_18;  

//Set precision level of floating point number

cout << fixed;

    cout << setprecision(6);

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hours_6 = n / 2.0;

hours_12 = hours_6 / 2.0;

hours_18 = hours_12 / 2.0;

//display the output

cout<<"After 6 hours: "<<hours_6<<"mg"<<endl;

cout<<"After 12 hours: "<<hours_12<<"mg"<<endl;

cout<<"After 18 hours: "<<hours_18<<" mg"<<endl;

return 0;

}

Explanation:

Read an input from the user. Set the precision to 6 for displaying the result up to 6 decimal places. The first half life at 6 hours can be calculated by dividing the input by 2. The half life at 12 hours can be found out by dividing the half life value at 6 hours by 2. Similarly at 18 hours, we find the half life value by dividing the half life value at 12 hours by 2.

Output:

Enter the initial value:100                                                                                                

After 6 hours: 50.000000 mg                                                                                                

After 12 hours: 25.000000 mg                                                                                              

After 18 hours: 12.500000 mg  

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The problem solving process begins by first ______ the problem.
alexandr402 [8]

Answer:

identifying/acknowledging

Explanation:

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