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LiRa [457]
2 years ago
14

There are 100 freshman students at a school. The probability that a freshman plays a sport is 0.55. The probability that a fresh

man plays a musical instrument is 0.34. The probability that a freshman plays both a sport and a musical instrument is 0.15. What is the probability that a freshman student at this school plays either a sport or a musical instrument?
Mathematics
1 answer:
Lina20 [59]2 years ago
5 0

The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74

Step-by-step explanation:

The addition rules in probability are:

  • P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen at the same time)
  • P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they have at least one outcome in common)

∵ The probability that a freshman plays a sport is 0.55

∴ P(sport) = 0.55

∵ The probability that a freshman plays a musical instrument is 0.34

∴ P(music) = 0.34

∵ The probability that a freshman plays both a sport and a musical

    instrument is 0.15

∴ P(sport and music) = 0.15

To find the probability that freshman student at this school plays either a sport or a musical instrument use the second rule above because it is non-mutually exclusive

∵ P(sport or music) = P(sport) + P(music) - P(sport and music)

∴ P(sport or music) = 0.55 + 0.34 - 0.15

∴ P(sport or music) = 0.74

The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74

Learn more:

You can learn more about the probability in brainly.com/question/9178881

#LearnwithBrainly

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I'm assuming this was the answer to yur question?
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2 years ago
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erik [133]

Answer: Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

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Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

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P(female or between 18-20) =  0.42+0.39-0.16

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3 0
2 years ago
Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx
IrinaK [193]

Answer:

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Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>

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using Mid-point method                          = <u> Q2-Q1           </u>  × 100

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                                      = <u>1.3-1.2           </u>   × 100

                                        (1.2+1.3)÷2

                                     = <u>0.1      </u> × 100

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                                     = 8%

% change in price of FedEx

using midpoint method    =<u> P2-P1            </u>× 100

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6 0
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tatiyna
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\frac{1}{5} is equivalent to 20%, which as a decimal is 0.2

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Answer:

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Step-by-step explanation:

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To Find:

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Solution:

Let x be the number of times he wants to visit

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3.50x = 40

x = \frac{40}{3.50}

x =  11.42

x = 11 (approx)

3 0
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