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1 year ago

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On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above

and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1On a coordinate plane, a solid straight line has a positive slope and goes through (0, negative 1) and (3, 0). Everything above and to the left of the line is shaded. Which linear inequality is represented by the graph? y ≤ One-thirdx − 1 y ≥ One-thirdx − 1 y < 3x − 1 y > 3x − 1

2 answers:

Charra [1.4K]1 year ago

8 0

Answer:

$y\geq\frac{1}{3}x-1$

Step-by-step explanation:

A solid straight line has a positive slope and goes through (0, negative 1) and (3, 0)

<em>Find the slope of the solid line</em>

$m=(0+1)/(3-0)\\\\m=\frac{1}{3}$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=\frac{1}{3}$

$b=-1$ ---> given problem

substitute

$y=\frac{1}{3}x-1$

Everything above and to the left of the line is shaded

so the inequality is equal to

$y\geq\frac{1}{3}x-1$

professor190 [17]1 year ago

5 0

Answer:

Step-by-step explanation:

its B just took the quiz

y ≥ One-thirdx − 1

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