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podryga [215]
2 years ago
11

Peter's salary is twice Anne's salary and half of David's salary. Then the average salary of Anne and David is _ of Peter's sala

ry​
Mathematics
1 answer:
satela [25.4K]2 years ago
6 0
<h3><u>Answer:</u></h3>

Average of salary of Anne and David is 1.25 of Peter's Salary

<h3><u>Explanation:</u></h3>

In the question, relations between salaries of Peter, Anne, and David is given. From the given relations, we need to make few equations and calculate the average of Anne and David in terms of Peter's Salary.

Let us assume Peter's Salary as P.

Then we can calculate Anne's salary A = \frac{P}{2}.

Also David's salary = D = 2 \times P

Average of Anne's and David's salary = \frac{A+D}{2}

Average of Anne's and David's salary  = \frac{\frac{P}{2} + 2 \times P}{2}

Average of Anne's and David's salary  = \frac{5 \times P}{4}

Average = 1.25 \times P

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Step-by-step explanation:

I use  84+ CE

stat edit, then fill in the #s

then

vars 5

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2'nd stat plot, on

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then click (4)(LinReg(ax+b))

then click enter 5 times

(y=-25.31428571x+1000.285714

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now, lets use computer:

y=-25.31(543)+1000.3

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this doesn't really work, so I will put 1999, 2000, 2001, 2002, 2003, 2004 instead of 0, 1, 2, 3, 4, 5 and do the same thing

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2 years ago
Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos
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We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

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