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marta [7]
1 year ago
12

A young channel catfish weighs about 0.1 pound. During the next 8 weeks, its weight increases by about 23% each week. About how

much will the catfish weigh after 4 weeks? Round your answer to the nearest thousandth of a pound.
Mathematics
1 answer:
katen-ka-za [31]1 year ago
3 0

Weight after 4 weeks is 0.229 pound

<em><u>Solution:</u></em>

Given that young channel catfish weighs about 0.1 pound

During the next 8 weeks, its weight increases by about 23% each week

So the exponential growth function is given as:

Exponential functions are given by

y = a(1+r)^x

where a is the initial amount, r is the rate of growth, and x is the amount of time and y is the weight after "x" weeks

In our case, a = 0.1, r = 0.23 ( that is 23 % ) and t = 4

Thus we get,

y = 0.1(1 + 0.23)^4

y = 0.1(1.23)^4\\\\y = 0.1 \times 2.289\\\\y = 0.229

Thus weight after 4 weeks is 0.229 pound

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Frank started out in his car travelling 45 mph. When Frank was 1 3 miles away, Daniel started out from the same point at 50 mph
oee [108]

Answer:

It will take 2.6 hours by Daniel to catch up with Frank.

Step-by-step explanation:

Let Daniel will catch up with Frank after t hours.

Now, Frank will go 13 miles in \frac{13}{45} = 0.288 hours.

So, the distance traveled by Frank in (t + 0.228) hours with 45 mph speed will be equal to the distance traveled by Daniel in t hours with 50 mph speed.

Hence, 45(t + 0.288) = 50t

⇒ 5t = 13

⇒ t = 2.6 hours.

Therefore, it will take 2.6 hours by Daniel to catch up with Frank. (Answer)

8 0
2 years ago
The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat
Greeley [361]

Answer:

1) L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

2) T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

3) T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

L \propto T^2

Using the condition given:

2.205 m = K (3)^2

K = 0.245 \approx \frac{g}{4\pi^2}

So then if we want to create an equation we need to do this:

L = K T^2

With K a constant. For this case the period of a pendulumn is given by this general expression:

T = 2\pi \sqrt{\frac{L}{g}}

Where L is the length in m and g the gravity g = 9.8 \frac{m}{s^2}.

Part 2

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

If we square both sides of the equation we got:

T^2 = 4 \pi^2 \frac{L}{g}

And solving for L we got:

L = \frac{g T^2}{4 \pi^2}

Replacing we got:

L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m

Part 3

For this case using the function in part a we got:

T = 2\pi \sqrt{\frac{L}{g}}

Replacing we got:

T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s

8 0
2 years ago
Justin weighs 15 pounds less than Greg weighs. Half of Greg’s weight is 75 pounds less than Justin’s weight. How much does each
sp2606 [1]
Lets take Gregs weight as “x”. This means that Justins weight is x-15, and x/2 = (x-15)-75.

If we take that last equation, lets combine like terms:

x/2 = x - 15 - 75
x/2 = x - 90
Now multiply both sides by 2 to get rid of the fraction
x = 2x - 180
Subtract 2x from both sides
x - 2x = -180
-x = -180
x = 180 — this is Gregs weight

Justins weight is x-15, so 180-15, which is 165 pounds. Hope this helped.
5 0
1 year ago
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