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Tresset [83]
2 years ago
12

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

Mathematics
1 answer:
BabaBlast [244]2 years ago
5 0

Answer:

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

Step-by-step explanation:

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

The solution is attached.

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One month julia collected 8.4 gallons of rainwater. That month she used 5.2 gallons of rainwater to water her garden and 6.5 gal
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Given

One month julia collected 8.4 gallons of rainwater.

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To proof

As given in the question

One month julia collected 8.4 gallons of rainwater

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Total water she used in the month = 5.2 gallons + 6.5gallons

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