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Tresset [83]
2 years ago
12

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

Mathematics
1 answer:
BabaBlast [244]2 years ago
5 0

Answer:

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

Step-by-step explanation:

Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)

r = 1/2

c1 = 3/4

c2 = 27/64

c3 = 405/1408

The solution is attached.

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this explains solution:

1/3x = 1/4

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Answer:

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Step-by-step explanation:

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Answer:

See the figure attached

Step-by-step explanation:

Let's call :

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then the score is:

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Two angles in a triangle measure 33 degrees and 112 degrees. What is the measure of the third angle?
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