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mash [69]
2 years ago
12

Katie wants to collect over 100100100 seashells. She already has 343434 seashells in her collection. Each day, she finds 121212

more seashells on the beach. Katie can use fractions of days to find seashells.
Write an inequality to determine the number of days, ddd, it will take Katie to collect over 100100100 seashells.
Mathematics
2 answers:
Elden [556K]2 years ago
8 0

Katie wants to collect over 100 seashells. She already has 34 seashells in her collection. Each day, she finds 12 more seashells on the beach. Katie can use fractions of days to find seashells.

Write an inequality to determine the number of days, d, it will take Katie to collect over 100 seashells

<em><u>Answer:</u></em>

Kathie needs more than 5 days to get over 100 shells

The required inequality is 34 + 12d > 100

<em><u>Solution:</u></em>

Given that,

Katie wants to collect over 100 seashells.

She already has 34 seashells in her collection.

Each day, she finds 12 more seashells on the beach

Let "d" be the number of days she takes to cover 100 sea shells

From given statement,

She finds 12 seashells each day

Then for "d" days, the number of sea shells she collected is 12d

She already had = 34

So, the equation can be framed as:

34 + 12d > 100

Here we used "greater than" symbol, since she wants to collect over 100 seashells

Solve the inequality

12d >100-34\\\\12d>66\\\\d>\frac{66}{12}\\\\d>5.5

This means she won't have more than  100 shells until the 6th day

Thus she needs more than 5 days to get over 100 shells

larisa [96]2 years ago
8 0

Answer:

34+12d>100

Step-by-step explanation:

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Answer & Explanation:

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Wheel A has a diameter of 25.4 inches. Wheel B has a diameter of 22.5 inches. About how much farther will Wheel A travel in one
MissTica

Wheel A will travel a distance of approximately 9 in more than wheel B in one rotation.

<u>Explanation:</u>

Given:

Diameter of wheel A, d₁ = 25.4 in

Radius of wheel A, r₁ = 12.7 in

Diameter of wheel B = 22.5 in

Radius of Wheel B, d₂ = 11.25 in

Distance travelled by A = ?

In one rotation, the distance travelled by a wheel is equal to its circumference.

Circumference of a wheel = 2πr

Circumference of wheel A = 2πr₁

                                            = 2 X 3.14 X 12.7 in

                                            = 80 in

Circumference of wheel B = 2πr₂

                                              = 2 X 3.14 X 11.25 in

                                              = 71 in

Therefore, wheel A will travel a distance of approximately 9 (80 - 71 in) in more than wheel B in one rotation.

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2 years ago
Consider a specific chemical reaction represented by the equation aa + bb → cc + dd. in this equation the letters a, b, c, and d
noname [10]
We are usually concerned with one reaction. That is, the production of one specific set of products from a specific set of reactants.

The number of values of c/d would be the number of possible ways that a and b could recombine to form different pairs of products c and d. (You might get different reactions at different temperatures, for example. Or, you might get different pars of ions.)

Usually, the number of values of c/d is one (1). (Of course, if you simply swap what you're calling "c" and "d", then you double that number, whatever it is.)
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A hockey player strikes a hockey puck. The height of the puck increases until it reaches a maximum height of 1.5 feet, 30 feet a
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Answer:

x₁ > x₂

Step-by-step explanation:

Both actions imply a parable trajectories, since both are projectile shot cases.

Let´s call x₁ maximum distance in the first case

The maximum height is just in the middle of the curve, therefore x₁ the maximum horizontal distance is equal to 60 feet.

In the second case, the parable curve is modeled by:

y = x₂*( 0.08 - 0.002x₂)    or  y = 0.08*x₂ - 0.002*x₂²

A second degree equation, solving for x₂ and dismissing the value x₂ = 0

we get:

y = 0       ⇒    x₂*( 0.08 - 0.002x₂) = 0    x₂ = 0

And 0,08 - 0.002*x₂ = 0

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x₂ = 0.08/0.002

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Then  x₁ > x₂

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Given that you did not include the diagram showing the circle, the tangent line and the points Q, R, and S, I am going to give you the explanation to answer the question.

1) The tangent lines to a circle form a 90° angle with the radius at the point of intersection.

2) Therefore, if the point of intersection of the tangent line and the circle is named R, and the points S and Q are one the center of the circle and the other is on the line RQ, then you know that the segment SR is a radius and the line RQ is the tangent, which means that they are perpendicular, i.e. the angle QRS is measures 90°.

In this case the answer is m angle QRS = 90°.

3) Otherwise the angle is different to 90° and you need to observe the figure to conclude whether it is greater than 90°, less than 90° or there is not enough information.
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