6 ones 7 hundredths -2.3
We make a place chart for 6 ones 7 hundredths. We write 0 in the remaining place value.
Hundred tens Ones point tenths hundredths thousandths
0 0 6 . 0 7 0
6 one 7 hundredths is 6.07
Now subtract 2.3 from 6.07
6.07 - 2.3 = 3.77
Answer : 3.77
Seems to be that the limit to compute is

Consider an arbitrary line through the origin

, so that we rewrite the above as

The value of the limit then depends on the slope

of the line chosen, which means the limit is path-dependent and thus does not exist.
Answer:
1.734
Step-by-step explanation:
Given that:
A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).
The fitted regression is Time = −7.126 + .0214 Distance
Based on a sample size n = 20
And an Estimated standard error of the slope = 0.0053
the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:
Let's determine the degree of freedom df = n - 1
the degree of freedom df = 20 - 2
the degree of freedom df = 18
At the level of significance ∝ = 0.05 and degree of freedom df = 18
For a right tailed test t, the critical value from the t table is :
1.734
Answer:
i hope this helps
Step-by-step explanation:
The answer would be A, or "A box-and-whisker plot. The number line goes from 0 to 12, and the box ranges from 4 to 10. A line divides the box at 7.
Step-by-step explanation:
If you plot the data (2, 4, 6, 8, and 12) it looks something like the poor box-and-whisker plot below
⊕← | Ф | →⊕
|---|---|---|---|---|---|---|---|---|---|---|---|
0 1 2 3 4 5 6 7 8 9 10 11 12
Description A describes that exact box-and-whisker plot.