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soldier1979 [14.2K]
2 years ago
13

Form the recurrence relations (RRs) for the number of vertices and the number of edges of a hypercube of n dimensions, Hn. Solve

the RRs.
Computers and Technology
1 answer:
Rus_ich [418]2 years ago
8 0
I'll write it below Step-by-step explanation: Q1 a side that has 10 sides and 10 angles is called decagon. Q2 it is nonagon Q3 it is Pentagon Q4it is heptagon
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Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both doubles) as input, and output the g
I am Lyosha [343]

Answer:

#program in Python.

#function to calculate driving cost

def driving_cost(d_miles, m_per_gallon, doll_per_gallon):

   #calculate cost and return the value

   return (d_miles / m_per_gallon) * doll_per_gallon

#read the miles per gallon  

m_per_gallon = float(input("Enter car's miles/gallon:"))

#read dollars per gallon

doll_per_gallon = float(input("Enter gas dollars/gallon:"))

#call function to find cost for 10 miles

print('%0.2f' % driving_cost(10, m_per_gallon, doll_per_gallon))

#call function to find cost for 50 miles

print('%0.2f' % driving_cost(50, m_per_gallon, doll_per_gallon))

#call function to find cost for 400 miles

print('%0.2f' % driving_cost(400, m_per_gallon, doll_per_gallon))

Explanation:

Read the value of miles per gallon and assign it to variable "m_per_gallon". Then read dollars per gallon from user and assign it to variable "doll_per_gallon". Call the function driving_cost() with parameter miles, m_per_gallon and doll_per_gallon. This function will find the cost of driving and return the cost.Call function for  10, 50 and 400 miles.

Output:

Enter car's miles/gallon:20                                                                                                

Enter gas dollars/gallon:3.1599                                                                                            

1.58                                                                                                                      

7.90                                                                                                                      

63.20

5 0
2 years ago
Read 2 more answers
. Question 2 Fill in the blank: R Markdown notebooks can be converted into HTML, PDF, and Word documents, slide presentations, a
Levart [38]

R markdown notebook describes a notebook format in R programming which supports R programmers to run codes while also writing documents or explanation alongside. Hence, the missing option is Dashboard.

  • R markdown may be compared to jupyter notebooks which also supports writing in markdown language.

  • The R markdown notebooks can be created using the R studio, which allows the conversion notebooks of these notebooks into several different formats including the creation of dashboards.

Hence, R markdown notebooks can be converted to <em>HTML</em><em> </em><em> </em><em> </em><em>PDF</em><em>,</em><em> </em><em>word</em><em> </em><em>document</em><em>,</em><em> </em><em>slide</em><em> </em><em>presentation</em><em> </em><em>and</em><em> </em>dashboards.

Learn more :brainly.com/question/25575402

3 0
2 years ago
(Displaying a Sentence with Its Words Reversed) Write an application that inputs a line of text, tokenizes the line with String
Serjik [45]

Answer:

I am writing a JAVA and Python program. Let me know if you want the program in some other programming language.

import java.util.Scanner; // class for taking input from user

public class Reverse{ //class to reverse a sentence

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); //create a Scanner class object

   System.out.print("Enter a sentence: "); //prompts user to enter a sentence

   String sentence = input.nextLine(); // scans and reads input sentence

   String[] tokens = sentence.split(" "); // split the sentence into tokens using split() method and a space as delimiter

   for (int i = tokens.length - 1; i >= 0; i--) { //loop that iterates through the tokens of the sentence in reverse order

       System.out.println(tokens[i]); } } } // print the sentence tokens in reverse order

Explanation:

In JAVA program the user is asked to input a sentence. The sentence is then broken into tokens using split() method. split method returns an array of strings after splitting or breaking the sentence based on the delimiter. Here the delimiter used is space characters. So split() method splits the sentence into tokens based on the space as delimiter to separate the words in the sentence. Next the for loop is used to iterate through the tokens as following:

Suppose the input sentence is "How are you"

After split() method it becomes:

How

are

you

Next the loop has a variable i which initialized to the tokens.length-1. This loop will continue to execute till the value of i remains greater than or equals to 0.

for (int i = tokens.length - 1; i >= 0; i--)

The length of first token i.e you is 3 so the loop executes and prints the word you.

Then at next iteration the value of i is decremented by 1 and now it points at the token are and prints the word are

Next iteration the value of i is again decremented by i and it prints the word How.

This can be achieved in Python as:

def reverse(sentence):

   rev_tokens = ' '.join(reversed(sentence.split(' ')))

   return rev_tokens

   

line = input("enter a sentence: ")

print((reverse(line)))

The method reverse takes a sentence as parameter. Then rev_tokens = ' '.join(reversed(sentence.split(' ')))  statement first splits the sentence into array of words/tokens using space as a delimiter. Next reversed() method returns the reversed sentence.  Next the join() method join the reversed words of the sentence using a space separator ' '.join(). If you want to represent the reversed tokens each in a separate line then change the above statement as follows:

rev_tokens = '\n'.join(reversed(sentence.split(' ')))  

Here the join method joins the reversed words separating them with a new line.

Simply input a line of text and call this reverse() method by passing the input line to it.

4 0
2 years ago
Read the attached paper titled A Survey of Coarse-Grained Reconfigurable Architecture and comment on it. Make sure to specifical
Pani-rosa [81]

Answer:

lol

Explanation:

I NEED POINTS

5 0
1 year ago
For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a space. Ex: I
VARVARA [1.3K]

Answer:

import java.util.Scanner;  //mentioned in the question.

public class ArraysKeyValue {  //mentioned in the question.

public static void main (String [] args) {  //mentioned in the question.

final int SIZE_LIST = 4; //mentioned in the question.

int[] keysList = new int[SIZE_LIST]; //mentioned in the question.

int[] itemsList = new int[SIZE_LIST]; //mentioned in the question.

int i; //mentioned in the question.

keysList[0] = 13; //mentioned in the question.                                

keysList[1] = 47; //mentioned in the question.

keysList[2] = 71; //mentioned in the question.

keysList[3] = 59; //mentioned in the question.

itemsList[0] = 12; //mentioned in the question.

itemsList[1] = 36; //mentioned in the question.

itemsList[2] = 72; //mentioned in the question.

itemsList[3] = 54;//mentioned in the question.

// other line to complete the solution is as follows--

for(i=0;i<(keysList.length);i++) //Loop to access all the element of keysList array variable.

    {// open for loop braces

        if(keysList[i]>50) // compare the value of keysList array variable with 50.

        System.out.println(itemsList[i]); // print the value

   }// close for loop braces.

}//  close main function braces.

} //close the class braces.

Output:

72

54

Explanation:

In the solution part--

  1. One loop is placed which moves from 0 to (size-1) of the 'keyslist' array.
  2. Then the 'if' statement is used to check the element of 'keyslist' array, which is greater than 50 or not.
  3. If it is greater, then print the element of item_list array of 'i' index which is also the index of greater value of keyslist array element.

5 0
2 years ago
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