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patriot [66]
2 years ago
4

Which function represents exponential decay? f(x) = One-half(2)x f(x) = Three-fourths(Negative one-fifth)x f(x) = 3(Seven-halves

)x f(x) = 2(Two-thirds)x
Mathematics
2 answers:
almond37 [142]2 years ago
5 0

Answer:              f(x)=2(\dfrac{2}{3})^x

Step-by-step explanation:

We know that the exponential decay equation is given by :-

y=Ab^x

, where A = initial value.

b = Multiplicative growth rate  ( b <1 for decay)

x= time period.

Note : b ≠1 and b>0.

Let's check all the functions:

  • f(x)=\dfrac{1}{2}(2)^x

, here b =2 >1 , so this function does not represent exponential decay.

  • f(x)=\dfrac{3}{4}(-\dfrac{1}{5})

here b = -\dfrac{1}{5}  but b should be greater than 0 for exponential function, so this function does not represent exponential decay.

  • f(x)=3(\dfrac{7}{2})^x

Here , b=\frac{7}{2}>1 , so this function does not represent exponential decay.

  • f(x)=2(\dfrac{2}{3})^x

Here , b=\dfrac{2}{3}  , so this function represents exponential decay.

Hence, the correct answer is f(x)=2(\dfrac{2}{3})^x .

gizmo_the_mogwai [7]2 years ago
4 0

Answer:

D on edg

Step-by-step explanation:

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Answer:

He burnt 1000 calories per hour when playing basketball.

Step-by-step explanation:

Let B be calories burned playing basketball, and C calories burned canoing.

1800 = B + 2C

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From 1st equatipn, we get that B = 1800 - 2C

Replacing into the 2nd equation, we have:

3200 = 2(1800-2C) + 3C

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Answer:

A) P(t)=77.2\cdot e^{0.016t}

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C) In year 2017.

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A). We know that a continuous growth function is in form y=a\cdot e^{kx}, where,

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1.2305699481865285=e^{0.016t}

Take natural log of both sides:

\text{ln}(1.2305699481865285)=\text{ln}(e^{0.016t})

\text{ln}(1.2305699481865285)=0.016t\text{ln}(e)

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t=12.9673396606

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