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nexus9112 [7]
2 years ago
15

A car rental firm has the following charges for a certain type of car: $25 per day with 100 free miles included, $0.15 per mile

for more than 100 miles. Suppose you want to rent a car for one day, and you know you'll use it for more than 100 miles. What is the equation for relating the cost y to the number of miles x that you drive the car?
Mathematics
1 answer:
Eddi Din [679]2 years ago
7 0

y = 25 + 0.15x is the equation for relating the cost y to the number of miles x that you drive the car

<em><u>Solution:</u></em>

Let "y" be the total cost of car rental

Let "x" be the number of miles you drive the car for more than 100 miles

<em><u>A car rental firm has the following charges for a certain type of car:</u></em>

$25 per day with 100 free miles included, $0.15 per mile for more than 100 miles

<em><u>Suppose you want to rent a car for one day, and you know you'll use it for more than 100 miles</u></em>

Therefore,

Car is rented for one day

You will use it for more than 100 miles

Therefore, equation is framed as:

Total cost = $ 25 + 0.15(number of hours)

Total\ Cost = 25 + 0.15x\\\\y = 25 + 0.15x

Thus the equation for relating the cost y to the number of miles x that you drive the car

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Two parallel lines are crossed by a transversal. What is the value of D?
Sliva [168]

Answer:c

Step-by-step explanation:

4 0
2 years ago
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among a group of students 50 played cricket 50 played hockey and 40 played volleyball. 15 played both cricket and hockey 20 play
kondaur [170]

Answer:

Cricket only= 30

Volleyball only = 15

Hockey only = 25

Explanation:

Number of students that play cricket= n(C)

Number of students that play hockey= n(H)

Number of students that play volleyball = n(V)

From the question, we have that;

n(C) = 50, n(H) = 50, n(V) = 40

Number of students that play cricket and hockey= n(C∩H)

Number of students that play hockey and volleyball= n(H∩V)

Number of students that play cricket and volleyball = n(C∩V)

Number of students that play all three games= n(C∩H∩V)

From the question; we have,

n(C∩H) = 15

n(H∩V) = 20

n(C∩V) = 15

n(C∩H∩V) = 10

Therefore, number of students that play at least one game

n(CᴜHᴜV) = n(C) + n(H) + n(V) – n(C∩H) – n(H∩V) – n(C∩V) + n(C∩H∩V)

= 50 + 50 + 40 – 15 – 20 – 15 + 10

Thus, total number of students n(U)= 100.

Note;n(U)= the universal set

Let a = number of people who played cricket and volleyball only.

Let b = number of people who played cricket and hockey only.

Let c = number of people who played hockey and volleyball only.

Let d = number of people who played all three games.

This implies that,

d = n (CnHnV) = 10

n(CnV) = a + d = 15

n(CnH) = b + d = 15

n(HnV) = c + d = 20

Hence,

a = 15 – 10 = 5

b = 15 – 10 = 5

c = 20 – 10 = 10

Therefore;

For number of students that play cricket only;

n(C) – [a + b + d] = 50 – (5 + 5 + 10) = 30

For number of students that play hockey only

n(H) – [b + c + d] = 50 – ( 5 + 10 + 10) = 25

For number of students that play volleyball only

n(V) – [a + c + d] = 40 – (10 + 5 + 10) = 15

3 0
2 years ago
Robbie went parasailing. his sail reached 141 feet. it descended 22 feet before staying in the same place for 10 minutes. what w
mash [69]
141 minus 22 equals 119
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2 years ago
The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times
rusak2 [61]

Answer:

x=30\\y=68\\z=82

Step-by-step explanation:

x = measure of the first angle

y = measure of the second angle

z = measure of the third angle

The sum of the measures of the second and third (y+z) is five times the measure of the first angle (=5x)

y+z=5x

The third angle is 14 more than the second

z=y+14

And remember that the sum of these three angles must be equal to 180.

x+y+z=180

Let's take these equations

y+z=5x\\z=y+14\\x+y+z=180

If you take a look at the first equation, we have y+z = 5x and we have y+z in the third equation as well, we can replace that....

x+y+z=180\\x+(y+z)=180\\x+(5x)=180

Distribute the + sign

x+5x=180

Combine like terms;

6x=180

Divide by 6.

x=\frac{180}{6}\\ x=30

We have now defined that the measure of the first angle is 30º.

Let's take another equation... for example z=y+14

I'm going to take this one because if I replace x and z in the third equation, all I'll have left will be y.

x+y+z=180\\30+y+(y+14)=180

Distribute the + sign and Combine like terms;

30+y+y+14=180\\44+2y=180\\

Subtract 44 to isolate 2y.

2y=180-44\\2y=136

Now divide by 2.

y=\frac{136}{2}\\ y=68

We already have the value of x and y. Once again, replacing this in the third equation will leave us with z to solve for.

x+y+z=180\\30+68+z=180\\98+z=180\\z=180-98\\z=82

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2 years ago
A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year
Roman55 [17]

Answer:

The required equation is y = 18(1.15)^x.

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

y = 18(1.15)^x

Now verify this by substituting x=1 in above equation.

y = 18(1.15)^1=20.7

Which is true.

Hence, the required equation is y = 18(1.15)^x.

7 0
2 years ago
Read 2 more answers
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