answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scorpion4ik [409]
2 years ago
9

Which of the following is most likely to form multiple (double or triple) bonds? 1. Li 2. Cl 3. N 4. H 5. F

Chemistry
1 answer:
alukav5142 [94]2 years ago
3 0

Answer: Option (3) is the correct answer.

Explanation:

Atomic number of lithium is 3 and its electronic distribution is 2, 1. So, to attain stability it will loose an electron and hence, it forms a single bond.

Atomic number of chlorine is 17 and it has 7 valence electrons. Hence, in order to attain stability it will gain one electron and therefore, it forms a single bond only.

Atomic number of nitrogen is 7 and its electronic distribution is 2, 5. Therefore, to attain stability it needs to gain 3 more electrons. Hence, a nitrogen atom is able to form a triple bond and also it is able to form a double bond.

Hydrogen has atomic number 1 and it attains stability by gaining one electron. Therefore, a hydrogen atoms always forms a single bond.

Atomic number of fluorine is 9 and its electronic distribution is 2, 7. To complete its octet it needs to gain one electron. Hence, a fluorine atom always forms a single bond.

Thus, we can conclude that out of the given options nitrogen is most likely to form multiple (double or triple) bonds.

You might be interested in
Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown c
Alexus [3.1K]

Answer:

0.3229 M HBr(aq)

0.08436M H₂SO₄(aq)

Explanation:

<em>Stu Dent has finished his titration, and he comes to you for help with the calculations. He tells you that 20.00 mL of unknown concentration HBr(aq) required 18.45 mL of 0.3500 M NaOH(aq) to neutralize it, to the point where thymol blue indicator changed from pale yellow to very pale blue. Calculate the concentration (molarity) of Stu's HBr(aq) sample.</em>

<em />

Let's consider the balanced equation for the reaction between HBr(aq) and NaOH(aq).

NaOH(aq) + HBr(aq) ⇄ NaBr(aq) + H₂O(l)

When the neutralization is complete, all the HBr present reacts with NaOH in a 1:1 molar ratio.

18.45 \times 10^{-3} L NaOH.\frac{0.3500molNaOH}{1LNaOH} .\frac{1molHBr}{1molNaOH} .\frac{1}{20.00 \times 10^{-3} LHBr} =\frac{0.3229molHBr}{1LHBr} =0.3229M

<em>Kemmi Major also does a titration. She measures 25.00 mL of unknown concentration H₂SO₄(aq) and titrates it with 0.1000 M NaOH(aq). When she has added 42.18 mL of the base, her phenolphthalein indicator turns light pink. What is the concentration (molarity) of Kemmi's H₂SO₄(aq) sample?</em>

<em />

Let's consider the balanced equation for the reaction between H₂SO₄(aq) and NaOH(aq).

2 NaOH(aq) + H₂SO₄(aq) ⇄ Na₂SO₄(aq) + 2 H₂O(l)

When the neutralization is complete, all the H₂SO₄ present reacts with NaOH in a 1:2 molar ratio.

42.18 \times 10^{-3} LNaOH.\frac{0.1000molNaOH}{1LNaOH} .\frac{1molH_{2}SO_{4}}{2molNaOH} .\frac{1}{25.00\times 10^{-3}LH_{2}SO_{4}} =\frac{0.08436molH_{2}SO_{4}}{1LH_{2}SO_{4}} =0.08436M

6 0
2 years ago
Name one manufactured device or natural phenomenon that emits electromagnetic radiation in each of the following wavelengths: ra
Bas_tet [7]
Radio - Radio station transmits radio wavelength which is received by the
Radio. 
<span>
Microwaves - Microwave Oven to heat up foods. </span>

<span>IR (infrared) - TV remote Control, to transmit IR light to a sensor in the TV so it can do some functions like increasing the volume, changing the channel etc. </span>


<span>Visible light - Sunlight or Light Bulbs </span>

<span>Ultraviolet - UV Lamps for sun tan, for detecting forged money </span>

<span>X-rays - Chest X-ray machines, Backscatter Xray (body scanner in airport security)
</span>
Gamma rays - Gamma rays<span> Medical Equipment which are used to kill cancer cells, to sterilize medical </span>equipment<span> </span>
7 0
2 years ago
The combustion of propane is best described as an
GalinKa [24]
<h3><u>Answer;</u></h3>

Exothermic chemical reaction

<h3><u>Explanation;</u></h3>
  • Exothermic reactions are chemical reactions where the products have less energy that the reactants.
  • Exothermic reactions give off energy, usually in the form of heat, while endothermic reactions absorb energy.
  • The combustion of propane is definitely an exothermic reaction because it generates a lot of heat.

5 0
2 years ago
Express the quantity 556.2 x 10^-12 in each units<br> A.) ms<br> B.) ns<br> C.) ps<br> D.) fs
zavuch27 [327]
The answer:
we should know the meaning of each abbreviation:
ms means  millisecond, its value is 10^-3 s 
ns means  means  nanosecond,   its value is 10^-9 s
ps means  picosecond, its value is 10^-12 s
fs means  femtosecond, its value is 1x 10^15 s

<span>Expressions of the quantity 556.2 x 10^-12 are</span>
556.2 x 10^-12 =556.2 ps
556.2 x 10^-12 =556.2 x 10^-9 x 10^-3= 556.2 x 10^-9 ms
556.2 x 10^-12 = 556.2 x 10^-3 x 10^-9 = 556.2 x 10^-3 ns
556.2 x 10^-12 = 556.2 x 10^- 27 x 10^15 = 556.2 x 10^- 27 fs
6 0
2 years ago
When of benzamide are dissolved in of a certain mystery liquid , the freezing point of the solution is less than the freezing po
SOVA2 [1]

The given question is incomplete. The complete question is as follows.

When 70.4 g of benzamide (C_{7}H_{7}NO) are dissolved in 850 g of a certain mystery liquid X, the freezing point of the solution is 2.7^{o}C lower than the freezing point of pure X. On the other hand, when 70.4 g of ammonium chloride (NH_{4}Cl) are dissolved in the same mass of X, the freezing point of the solution is 9.9^{o}C lower than the freezing point of pure X.

Calculate the Van't Hoff factor for ammonium chloride in X.

Explanation:

First, we will calculate the moles of benzamide as follows.

    Moles of benzamide = \frac{mass}{\text{Molar mass of benzamide}}

                    = \frac{70.4 g}{121.14 g/mol}

                    = 0.58 mol

Now, we will calculate the molality as follows.

     Molality = \frac{\text{moles of solute (benzamide)}}{\text{solvent mass in kg}}

                   = \frac{0.58 mol}{0.85 kg}

                   = 0.6837

It is known that relation between change in temperature, Van't Hoff factor and molality is as follows.

      dT = i \times K_{f} \times m,

where,      dT = change in freezing point = 2.7^{o}C

                  i = van't Hoff factor = 1 for non dissociable solutes

      K_{f} = freezing point constant of solvent

                m = 0.6837

Therefore, putting the given values into the above formula as follows.

             dT = i \times K_{f} \times m,

            2.7^{o}C = 1 \times K_{f} \times 0.6837 m

            K_{f} = 3.949 C/m

Now, we use this K_{f} value for calculating i for NH_{4}Cl

So, moles of ammonium chloride are calculated as follows.

 Moles of NH_{4}Cl = \frac{70.4 g}{53.491 g/mol}

                            = 1.316 mol

Hence, calculate the molality as follows.

    Molality = \frac{1.316 mol}{0.85 kg}

                  = 1.5484

It is given that value of change in temperature (dT) = 9.9^{o}C. Thus, calculate the value of Van't Hoff factor as follows.

              dT = i \times K_{f} \times m

   9.9^{o}C = i \times 3.949 C/m \times 1.5484 m

                     i = 1.62

Thus, we can conclude that the value of van't Hoff factor for ammonium chloride is 1.62.

5 0
2 years ago
Other questions:
  • Determine the mass of oxygen in a 7.20 g sample of Al2(SO4)3.
    9·2 answers
  • Compute 4.659×104−2.14×104. Round the answer appropriately.
    13·2 answers
  • How many moles are in 8.30x10^23 molecules of H2o
    7·2 answers
  • Combustion of 8.652 g of a compound containing c, h, o, and n yields 11.088 g of coz, 3.780 g of h2o, and 3.864 g of no2. How ma
    9·1 answer
  • Which of the following solutions is a buffer? Check all that apply. Check all that apply. a solution made by mixing 100 mL of 0.
    12·2 answers
  • Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in
    15·1 answer
  • Nickel can be plated from aqueous solution according to the following half reaction. How long would it take (in min) to plate 29
    14·1 answer
  • Report the precise concentration of the undiluted stock solution #1 of TZ in micromoles per liter. This is your most concentrate
    7·1 answer
  • Please help me double-check my answer: Calculate the molarity of an aqueous solution that contains 36.5g KMnO4 and has a total v
    5·2 answers
  • A beaker holds 962 g of a brine solution that is 6.20 percent salt. If 123g of water are evaporated from the beaker, how much sa
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!