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ruslelena [56]
2 years ago
5

The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer. If

the connector is ever wet, the probability of a failure during the warranty period is 5%. If 90% of the connectors are kept dry and 10% are wet,what proportion of connectors fail during the warranty period?
Mathematics
1 answer:
rodikova [14]2 years ago
4 0

Answer:

1.4% of connectors fail during the warranty period.

Step-by-step explanation:

We have these following probabilities:

A 90% probability that a connector is kept dry.

A 10% probability that a connectors is wet.

If a connector is dry, an 1% probability of failling.

If a connector is wet, a 5% probability of failling.

What proportion of connectors fail during the warranty period?

This is 1% of 90% and 5% of 10%. So

P = 0.01*0.9 + 0.05*0.1 = 0.014

1.4% of connectors fail during the warranty period.

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The following numerically ordered sequence of numbers has a mean of 17 and a median of 18.
erastovalidia [21]

Answer:

a = 9

b = 19

Step-by-step explanation:

DO B FIRST

The mean is the average of all the terms (numbers) in the sequence

To find the average you find the sum of the terms and divided the sum by the number of terms there are.

The mean times the number of terms equals the sum of all the terms subtract the terms that you know from the sum to get A

a = 17(10)-7-12-15-17-19-20-22-24-25

a = 170-161

a = 9

The median is found by taking the average of the two middle terms

Our middle terms are 17 and B

the median times 2 equals the sum of the two terms and then subtract the term you know from the sum

b = 18(2)-17

b = 36-17

b = 19

5 0
2 years ago
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Point G is on segment FH such that it partitions segment FH into a ratio of 2:3.Point F is located at (5, 7) and point H is loca
Margarita [4]

Answer:

G = (9.4, 9,4)

Step-by-step explanation:

The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH

x-distance:

x2 - x1 = 16 - 5 = 11

11/5 = 2.2

y-distance:

y2 - y1 = 13 - 7 = 6

6/5 = 1.2

Point G = Point F + (2.2*2, 1.2*2)

Point G = (5, 7) + (4.4, 2.4)

= (9.4, 9.4)

8 0
2 years ago
Which graph represents the function f (x) = StartFraction 1 Over x + 3 EndFraction minus 2? On a coordinate plane, a hyperbola i
Ede4ka [16]

Answer:

its A

Step-by-step explanation:

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5 0
2 years ago
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What is the value of x in this equation: 4x + 5 = 3x + 4? Solve the equation using the algebra tiles.
Snowcat [4.5K]

Answer:

x = -1

Step-by-step explanation:

4x + 5 = 3x + 4

      -5           -5

4x =    3x -1

-3x =   -3x

1x = -1

x = -1

4 0
2 years ago
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The graph shows the solution to the initial value problem y'(t)=mt, y(t0)= -4
Charra [1.4K]
y'(t)=mt
\\
\\ y=\int {mt} \, dt=m \int{t} \,dt=m \frac{t^2}{2} +C \\ \\y= \frac{mt^2}{2}+C

Now find equation of the graph. It passes through the point (2,3), and intersects y-axis at -2.

y=at^2+b
\\
\\3=a\times 2^2-2
\\
\\3=4a-2
\\
\\5=4a
\\
\\a= \frac{5}{4} 
\\
\\y=\frac{5}{4} t^2-2 \\ \\y= \frac{m}{2} t^2+C
\\ \\  \frac{m}{2} = \frac{5}{4} 
\\
\\m= \frac{5}{2} 
\\
\\C=-2
\\
\\y(t_0)=-4
\\
\\-4= \frac{5}{4} t_0^2-2
\\
\\ -2= \frac{5}{4} t_0^2
\\
\\ t_0^2=- \frac{8}{5} 
\\
\\t_0=\pm \sqrt{- \frac{8}{5} }



3 0
2 years ago
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